Problem 1 :
Can 30°, 60° and 90° be the angles of a triangle ?
Problem 2 :
Can 35°, 55° and 95° be the angles of a triangle ?
Problem 3 :
In a triangle, if the second angle is 5° greater than the first angle and the third angle is 5° greater than second angle, find the three angles of the triangle.
Problem 4 :
Find m∠W and m∠X in the triangle given below.
Problem 5 :
Find m∠A and m∠B in the triangle given below.
Problem 1 :
Can 30°, 60° and 90° be the angles of a triangle ?
Solution :
Let us add all the three given angles and check whether the sum is equal to 180°.
30° + 60° + 90° = 180°
Since the sum of the angles is equal 180°, the given three angles can be the angles of a triangle.
Problem 2 :
Can 35°, 55° and 95° be the angles of a triangle ?
Solution :
Let us add all the three given angles and check whether the sum is equal to 180°.
35° + 55° + 95° = 185°
Since the sum of the angles is not equal 180°, the given three angles can not be the angles of a triangle.
Problem 3 :
In a triangle, if the second angle is 5° greater than the first angle and the third angle is 5° greater than second angle, find the three angles of the triangle.
Solution :
Let x be the first angle.
The second angle = x + 5
The third angle = x + 5 + 5 = x + 10
We know that,
the sum of the three angles of a triangle = 180°
x + (x+5) + (x+10) = 180°
3x + 15 = 180
3x = 165
x = 55
The first angle = 55°
The second angle = 55 + 5 = 60°
The third angle = 60 + 5 = 65°
So, the three angles of a triangle are 55°, 60° and 65°.
Problem 4 :
Find m∠W and m∠X in the triangle given below.
Solution :
Step 1 :
Write the Exterior Angle Theorem as it applies to this triangle.
m∠W + m∠X = m∠WYZ
Step 2 :
Substitute the given angle measures.
(4y - 4)° + 3y° = 52°
Step 3 :
Solve the equation for y.
(4y - 4)° + 3y° = 52°
4y - 4 + 3y = 52
Combine the like terms.
7y - 4 = 52
Add 4 to both sides.
7y - 4 + 4 = 52 + 4
Simplify.
7y = 56
Divide both sides by 7.
7y / 7 = 56 / 7
y = 8
Step 4 :
Use the value of y to find m∠W and m∠X.
m∠W = 4y - 4
m∠W = 4(8) - 4
m∠W = 28
m∠X = 3y
m∠X = 3(8)
m∠X = 24
So, m∠W = 28° and m∠X = 24°.
Problem 5 :
Find m∠A and m∠B in the triangle given below.
Solution :
Step 1 :
Write the Exterior Angle Theorem as it applies to this triangle.
m∠A + m∠B = m∠C
Step 2 :
Substitute the given angle measures.
(5y + 3)° + (4y + 8)° = 146°
Step 3 :
Solve the equation for y.
(5y + 3)° + (4y + 8)° = 146°
5y + 3 + 4y + 8 = 146
Combine the like terms.
9y + 11 = 146
Subtract 11 from both sides.
9y + 11 - 11 = 146 - 11
Simplify.
9y = 135
Divide both sides by 9.
9y / 9 = 135 / 9
y = 15
Step 4 :
Use the value of y to find m∠A and m∠B.
m∠A = 5y + 3
m∠A = 5(15) + 3
m∠A = 75 + 3
m∠A = 78
m∠B = 4y + 8
m∠B = 4(15) + 8
m∠B = 60 + 8
m∠B = 68
So, m∠A = 78° and m∠B = 68°.
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Dec 30, 24 07:48 PM
Dec 30, 24 07:47 PM
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