In this section, you will learn how to write the equation of a line in slope intercept form.
Slope-intercept form equation of a line :
y = mx + b
Here 'm' stands for slope of the line and 'b' stands for y-intercept.
Example 1 :
Rewrite the following equation of a straight line in slope intercept form.
8x + 2y - 1 = 0
Solution :
8x + 2y - 1 = 0
Subtract 8x from each side.
2y - 1 = -8x
Add 1 to each side.
2y = -8x + 1
Divide each side by 2.
y = (-8x + 1) / 2
y = -8x/2 + 1/2
y = -4x + 1/2
Example 2 :
Rewrite the following equation of a straight line in slope intercept form.
3y - 2x + 9 = 0
Solution :
3y - 2x + 9 = 0
Add 2x to each side.
3y + 9 = 2x
Subtract 9 from each side.
3y = 2x - 9
Divide each side by 3.
y = (2x - 9) / 3
y = 2x/3 - 9/3
y = 2x/3 - 3
Example 3 :
Rewrite the following equation of a straight line in slope intercept form.
y - 4 = -3(x - 3)
Solution :
y - 4 = -3(x - 3)
Distributive property.
y - 4 = -3x + 9
Add 4 to each side.
y = -3x + 13
Example 4 :
Rewrite the following equation of a straight line in slope intercept form.
y - 8 = (-1/2)(x + 4)
Solution :
y - 8 = (-1/2)(x + 4)
Distributive property.
y - 8 = -x/2 - 2
Add 8 to each side.
y = -x/2 + 6
Example 5 :
Rewrite the following equation of a straight line in slope intercept form.
6x - 2y - 10 = 0
Solution :
6x - 2y - 10 = 0
Add 2y to each side.
6x - 10 = 2y
Divide each side by 2.
(6x - 10) / 2 = y
6x/2 - 10/2 = y
3x - 5 = y
(or) y = 3x - 5
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