To simplify logarithmic expressions, you must be aware of the following three fundamentals laws of logarithms.
Law 1 :
Logarithm of product of two numbers is equal to the sum of the logarithms of the numbers to the same base.
That is,
logamn = logam + logan
Law 2 :
Logarithm of the quotient of two numbers is equal to the difference of their logarithms to the same base.
That is,
loga(m/n) = logam - logan
Law 3 :
Logarithm of a number raised to a power is equal to the power multiplied by the logarithm of the number to the same base.
That is,
logamn = nlogam
Change of Base :
logba = logxa ⋅ logbx
logba = logxa/logxb
Simplify each of the following expressions :
Example 1 :
log5 25 + log5 625
Solution :
= log525 + log5625
= log5(25 ⋅ 625)
= log5(52 ⋅ 54)
= log55(2 + 4)
= log556
= 6log55
= 6(1)
= 6
Example 2 :
log5 4 + log5 (1/100)
Solution :
= log54 + log5(1/100)
= log5(4 ⋅ 1/100)
= log5(1/25)
= log5(1/52)
= log55-2
= -2log55
= -2(1)
= -2
Example 3 :
log8 128 - log8 16
Solution :
= log8128 - log816
= log8(128/16)
= log88
= 1
Example 4 :
log3 2 ⋅ log4 3 ⋅ log5 4 ⋅ log6 5 ⋅ log7 6 ⋅ log8 7
Solution :
In the given expression, logarithms have bases.
First group the logarithms with the same base and simplify.
= (log32 ⋅ log43) ⋅ (log54 ⋅ log65) ⋅ (log76 ⋅ log87)
= log42 ⋅ log64 ⋅ log86
= log62 ⋅ log86
= log82
= 1/log28
= 1/log223
= 1/3(log22)
= 1/3(1)
= 1/3
Example 5 :
log7 21 + log7 77 + log7 88 - log7 121 - log7 24
Solution :
= log721 + log777 + log788 - log7121 - log724
= log7(21 ⋅ 77 ⋅ 88) - (log7121 + log724)
= log7(21 ⋅ 77 ⋅ 88) - log7(121 ⋅ 24)
= log7142296 - log72904
= log7(142296/2904)
= log749
= log772
= 2log77
= 2(1)
= 2
Example 6 :
log8 16 + log8 52 - 1/log13 8
Solution :
= log816 + log852 - 1/log138
= log816 + log852 - log813
= log8[(16 ⋅ 52)/13]
= log8(16 ⋅ 4)
= log864
= log882
= 2log88
= 2(1)
= 2
Example 7 :
5log10 2 + 2log10 3 - 6log64 4
Solution :
= 5log102 + 2log103 - 6log644
= 5log102 + 2log103 - (2 ⋅ 3) log644
= log10 25 + log10 32 - 2log64 43
= log1032 + log109 - 2log6464
= log1032 + log109 - 2 (1)
= log1032 + log109 - 2log1010
= log10(32 ⋅ 9) - log10102
= log10(288/100)
= log10(72/25)
Example 8 :
log10 8 + log10 5 - log10 4
Solution :
= log108 + log105 - log104
= log10[(8 ⋅ 5)/4]
= log10(40/4)
= log1010
= 1
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