4th GRADE MATH PRACTICE ONLINE

Problem 1 :

How many three digit numbers are there ?

(A) 800        (B) 850            (C) 900

Solution :

Available digits are

0, 1, 2, 3, 4, 5, 6, 7, 8, 9 

Number of three digit numbers

  =  10⋅10⋅10

  =  900

So, the number of three digit numbers are 900.

Problem 2 :

What is the roman numeral for 1000 ?

 (A  L            (B)  M                 (C)  C

Solution :

Roman numeral of 1000 is M.

Problem 3 :

Which of the following numbers are divisible 9?

 (A) 4268          (B)  3447        (C) 1342

Solution :

Sum of digits in (A) :

4268  ==> 4 + 2 + 6 + 8 ==>  20 (Not divisible by 9)

Sum of digits in (B) :

3447  ==> 3 + 4 + 4 + 7 ==>  18 (Divisible by 9)

Sum of digits in (C) :

1342  ==> 1 + 3 + 4 + 2 ==>  10 (Not divisible by 9)

So, 3447 is divisible by 9.

Problem 4 :

Write 800 in exponential form.

(A) 3⁵ x 2²         (B) 2⁵ x 5²         (C) 5⁵ x 3²

Solution :

800  =  2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 5 ⋅ 5

  =  2⁵ ⋅ 5²

Exponential form of 800 is 2⁵ ⋅ 5².

Problem 5 :

Two composite numbers which have no common factors are called mutually __________________.

(A)  Prime             (B)  Composite     (C)  None of these

Solution :

Two composite numbers which have no common factors are called mutually prime.

Problem 6 :

A milk man had 15 liters of milk in a vessel and 20 liters of milk in another vessel. Find the maximum capacity of a measuring jar which the milkman uses to measure milk from either vessel an exact number of times.

Solution :

To find the maximum capacity of a measuring jar which the milkman uses to measure milk from either vessel an exact number of times, we find highest common factor of 15 an d 20.

15  =  5 ⋅ 3

20  =  2 ⋅ 2 ⋅ 5

Highest common factor is 5.

So the answer is 5 liters.

Problem 7 :

Find the L.C.M of 48, 56, 72 and 108.

 (A) 3024              (B) 3115               (C) 1248

Solution :

Least common multiple  =  2 ⋅ 2 ⋅ 3 ⋅ 2 ⋅ 3 ⋅ 2 ⋅ 7 ⋅ 3

  =  3024

Problem 8 :

Find the value of 16.45 + 124.562 + 62.7 - 75.243

(A) 148.633          (B) 115.24        (C) 128.469

Solution :

  124.562 +

 16.45

  62.7

---------

203.712

----------

203.712 - 75.243  =  128.469

Problem 9 :

Fill in the blanks with suitable number 5.6 x _____ = 56

 (A) 10             (B) 100            (C) 1000

Solution :

5.6 x _____ = 56

The decimal is moved one digit to the right, so 5.6 is to be multiplied by 10 to get 56.

Problem 10 :

Simplify 1/5 ÷ 3

(A) 1/15            (B) 3/5              (C) 1/8

Solution :

1/5 ÷ 3  =  1/5 ⋅ 1/3

  =  1/15

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