Problem 1 :
Find m∠KLM, if m∠KLB = 26° and m∠BLM = 60°.
Problem 2 :
Find m∠FGH, if m∠FGB = 105° and m∠BGH = 54°.
Problem 3 :
Find m∠WDC, if m∠EDC = 145° and m∠EDW = 61°.
Problem 4 :
Find m∠IHQ, if m∠IHG = 176° and m∠QHG = 130°.
Problem 5 :
In the diagram shown below,
m∠FCD = x° + 41°
if m∠BCF = x° + 78°
m∠BCD = 95°
Find x.
Problem 6 :
In the diagram shown below,
m∠BJK = 146° + 2x°
m∠IJK = 172°
m∠IJB = 2x° + 26°
Find x.
Problem 7 :
In the diagram shown below,
m∠GFZ = 38°
m∠ZFE = 2x° + 122°
m∠GFE = x° + 163°
Find x.
Problem 8 :
In the diagram shown below,
m∠LMN = 135°
m∠LMV = -1° + 45x°
m∠VMN = 23x°
Find x.
Problem 1 :
Find m∠KLM, if m∠KLB = 26° and m∠BLM = 60°.
Solution :
By Angle Addition Postulate,
m∠KLB + m∠BLM = m∠KLM
26° + 60° = m∠KLM
86° = m∠KLM
Problem 2 :
Find m∠FGH, if m∠FGB = 105° and m∠BGH = 54°.
Solution :
By Angle Addition Postulate,
m∠FGB + m∠BGH = m∠FGH
105° + 54° = m∠KLM
159° = m∠KLM
Problem 3 :
Find m∠WDC, if m∠EDC = 145° and m∠EDW = 61°.
Solution :
By Angle Addition Postulate,
m∠EDW + m∠WDC = ∠EDC
61° + m∠WDC = 145°
Subtract 61° from each side.
m∠WDC = 84°
Problem 4 :
Find m∠IHQ, if m∠IHG = 176° and m∠QHG = 130°.
Solution :
By Angle Addition Postulate,
m∠IHQ + m∠QHG = m∠IHG
m∠IHQ + 130° = 145°
Subtract 130° from each side.
m∠IHQ = 15°
Problem 5 :
In the diagram shown below,
m∠FCD = x° + 41°
if m∠BCF = x° + 78°
m∠BCD = 95°
Find x.
Solution :
By Angle Addition Postulate,
m∠BCF + m∠FCD = ∠BCD
x° + 41° + x° + 78° = 95°
Simplify.
2x + 119 = 95
Subtract 119 from each side.
2x = -24
Divide each side by 2.
x = -12
Problem 6 :
In the diagram shown below,
m∠BJK = 146° + 2x°
m∠IJK = 172°
m∠IJB = 2x° + 26°
Find x.
Solution :
By Angle Addition Postulate,
m∠IJB + m∠BJK = m∠IJK
146° + 2x° + 2x° + 26° = 172°
Simplify.
4x + 172 = 172
Subtract 172 from each side.
4x = 0
Divide each side by 4.
x = 0
Problem 7 :
In the diagram shown below,
m∠GFZ = 38°
m∠ZFE = 2x° + 122°
m∠GFE = x° + 163°
Find x.
Solution :
By Angle Addition Postulate,
m∠GFZ + m∠ZFE = m∠GFE
38° + 2x° + 122° = x° + 163°
Simplify.
2x + 160 = x + 163
x = 3
Problem 8 :
In the diagram shown below,
m∠LMN = 135°
m∠LMV = -1° + 45x°
m∠VMN = 23x°
Find x.
Solution :
By Angle Addition Postulate,
m∠LMV + m∠VMN = m∠LMN
-1° + 45x° + 23x° = 135°
Simplify.
-1 + 68x = 135
68x = 136
x = 2
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