Problem 1 :
Find the area of the shape shown below.
Problem 2 :
Find the area of the shape shown below.
Problem 3 :
Find the area of the shape shown below.
Problem 1 :
Find the area of the shape shown below.
Solution :
By drawing a horizontal line, we can divide the given shape into two parts (triangle and rectangle) as shown below.
(1) BECF is a rectangle
(2) ABD is triangle
Area of the given shape :
= Area of rectangle BECF + Area of triangle ABD
Area of rectangle BECF :
length CF = 16 cm and width BC = 7 cm
= length x width
= 16 x 7
= 112 cm2 ----(1)
Area of triangle ABD :
Base BD = BE - DE ----> 16 - 8 = 8 cm.
Height AB = AC - BC ----> 13 - 7 = 6 cm.
Area of triangle ABD = (1/2) x b x h
= (1/2) x 8 x 6 ==> 24 cm2----(2)
Area of the given shape :
= (1) + (2)
= 112 + 24
= 136 cm2
Problem 2 :
Find the area of the shape shown below.
Solution :
By drawing a horizontal line, we can divide the given shape into two rectangles.
(1) ABCD is a rectangle
(2) CEFG is rectangle
Area of the given polygon
= Area of rectangle ABCD + Area of triangle DEFG
Area of rectangle ABCD :
length AB = 20 ft and
width AC = AG - CG ----> 60- 30 = 30 ft
= length x width
= 20 x 30
= 600 ft2 ----(1)
Area of triangle DEFG :
length GF = 60 ft
width FE = 30 ft
= length x width
= 60 x 30
= 1800 ft2 ----(1)
Area of the given shape :
= (1) + (2)
= 600 + 1800
= 2400 ft2
Problem 3 :
Find the area of the shape shown below.
Solution :
Extend the top edge and the right edge of the polygon.
By subtracting the area of triangle BFB from the rectangle ABCD, we can find the area of the given shape.
Area of the given polygon :
= Area of rectangle ABCD - Area of triangle GFB
Area of rectangle ABCD :
length AD = 36 inches and
width AB = 18 inches
= length x width
= 36 x 18
= 648 in2 ----(1)
Area of triangle GFB :
base FG = 9 inches and
Height FB = AB - AF ==> 36 - 18 ==> 18 inches.
= (1/2) x base x height
= (1/2) x 9 x 18
= 81 in2 ----(2)
Area of the given shape :
= (1) - (2)
= 648 - 81
= 567 in2
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