AREA OF TRAPEZOID WORKSHEET

Problem 1 :

Find the area of the trapezoid ABCD shown below. 

Problem 2 :

In a trapezoid the measurement of one parallel side two more than the other parallel side and the height is 4 cm. The area of the trapezoid is 64 cm². Find the lengths of the two parallel sides.

Problem 3 :

The shape of the top surface of a table is a trapezoid. Find its area, if its parallel sides are 1 m and 1.2 m and perpendicular distance between 0.8 m.

Problem 4 :

The wall is in the shape as shown below has to be painted. If one can of paint covers 0.5 m², how many cans of paint will be needed, if only one coat of paint is applied ?

Problem 1 :

Find the area of the trapezoid ABCD shown below. 

Solution :

Area of the trapezoid ABCD is

=  (1/2)(a + b)h

Substitute a  =  5, b  =  12 and h  =  4.

=  (1/2)(5 + 12)4

=   (1/2)(17)4

=  34 cm² 

Problem 2 :

In a trapezoid the measurement of one parallel side two more than the other parallel side and the height is 4 cm. The area of the trapezoid is 64 cm². Find the lengths of the two parallel sides.

Solution :

Let 'a' and 'b' be the two parallel sides.

One parallel side is two more than the other parallel side.

Then, 

a  =  b + 2

Area of the trapezium  =  64 cm²

(1/2)(a + b)h  =  64

Substitute h  =  4 and a  =  b + 2. 

(1/2)(b + 2 + a)4 = 64

(2b + 2)2  =  64

Divide each side by 2. 

2b + 2  =  32

Subtract 2 from each side. 

2b  =  30

Divide each side by 2. 

b  =  15

Then, 

a  =  b + 2

a  =  15 + 2

a  =  17

So, the lengths of the two parallel sides are 15 cm and 17 cm.

Problem 3 :

The shape of the top surface of a table is a trapezoid. Find its area, if its parallel sides are 1 m and 1.2 m and perpendicular distance between 0.8 m.

Solution :

Area of a the top of surface of the table (trapezoid) is

=  (1/2)(a + b)h

=  (1/2)(1.2 + 1)0.8 

=  (1/2) (2.2)0.8 

=  1.1 (0.8)

=  8.8 m²

Problem 4 :

The wall is in the shape as shown below has to be painted. If one can of paint covers 0.5 m², how many cans of paint will be needed, if only one coat of paint is applied ?

Solution : 

In the figure shown above, the perpendicular distance between the two sides BC and AB at any point is same, which is 5 cm. 

Then, the sides BC and AD are parallel. 

In the quadrilateral above, because the two sides BC and AD are parallel, ABCD is a trapezoid. 

Let 'a' and 'b' be the lengths of two parallel sides and. 

a  =  BC  =  5cm

b  =  AD  =  AF + FE + ED  =  3 + 5 + 4  =  12 cm

Height (h)  =  5 cm  

Area of the trapezoid ABCD is 

=   (1/2)(a + b)h

Substitute a  =  5, b  =  12 and h  =  5.

=  (1/2)(5 + 12)5

=  42.5 m²

One can of paint covers 0.5 m².

Number of cans of paint required 42.5 m² is

=  42.5 / 0.5

=  425 / 5

=  85

So, 85 cans of paint required to cover the above wall. 

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