The centroid of a triangle is the point of concurrency of the medians.
In the above triangle , AD, BE and CF are called medians. All the three medians AD, BE and CF are intersecting at G. So G is called centroid of the triangle
If the coordinates of A, B and C are (x1, y1), (x2, ,y2) and (x3, y3), then the formula to determine the centroid of the triangle is given by
Example 1 :
Find the centroid of a triangle whose vertices are the points (8, 4), (1, 3) and (3, -1).
Solution :
Formula to find centroid of a triangle is
= [(x1 + x2 + x3)/3, (y1 + y2 + y3)/3]
x1 = 8, x2 = 1 and x3 = 3
y1 = 4, y2 = 3 and y3 = -1
= [(8 + 2 + 3)/3, (4 + 3 - 1)/3]
= (12/3, 6/3)
= (4, 2)
So, the centroid of the given triangle is (4, 2).
Example 2 :
Find the centroid of a triangle whose vertices are the points (6, -1), (8, 3) and (10, -5).
Solution :
Formula to find centroid of a triangle is
= [(x1 + x2 + x3)/3, (y1 + y2 + y3)/3]
x1 = 6, x2 = 8 and x3 = 10
y1 = -1, y2 = 3 and y3 = -5
Then,
= [(6 + 8 + 10)/3, (-1 + 3 - 5)/3]
= (24/3, -3/3)
= (8, -1)
So, the centroid of the given triangle is (8, -1).
Example 3 :
If a triangle has its centroid at (4, 3) and two of its vertices are (2, -1) and (7, 8), find the third vertex.
Solution :
Let (a, b) be the third vertex.
Centroid of the triangle = (4, 3)
[(x1 + x2 + x3)/3, (y1 + y2 + y3)/3] = (4, 3)
x1 = 2, x2 = 7 and x3 = a
y1 = -1, y2 = 8 and y3 = b
Then,
[(2 + 7 + a)/3, (-1 + 8 + b)/3] = (4, 3)
[(9 + a)/3, (7 + b)/3] = (4, 3)
Equate the coordinates of x and y.
(9 + a)/3 = 4 9 + a = 12 a = 3 |
(7 + b)/3 = 3 7 + b = 9 b = 2 |
So, the third vertex is (3, 2).
Example 4 :
If the centroid of a triangle is (-2, 1) and two of its vertices are (1, -6) and (-5, 2), then find the third vertex.
Solution :
Let (a, b) be the third vertex.
Centroid of the triangle = (-2, 1)
[(x1 + x2 + x3)/3, (y1 + y2 + y3)/3] = (-2, 1)
x1 = 1, x2 = -5 and x3 = a
y1 = -6, y2 = 2 and y3 = b
Then,
[(1 - 5 + a)/3, (-6 + 2 + b)/3] = (-2, 1)
[(-4 + a)/3, (-4 + b)/3] = (-2, 1)
Equate the coordinates of x and y.
(-4 + a)/3 = -2 -4 + a = -6 a = -2 |
(-4 + b)/3 = 1 -4 + b = 3 b = 7 |
So, the third vertex is (-2, 7).
Example 5 :
Master gave a triangular plate with vertices (5, 8), (2, 4) and (8, 3) and a stick to a student. He wants to balance the plate on the stick. Can you help the boy to locate that point which can balance the plate ?
Solution :
The point which can balance the triangular plate is the centroid of the triangle.
Formula to find centroid of a triangle is
= [(x1 + x2 + x3)/3, (y1 + y2 + y3)/3]
x1 = 5, x2 = 2 and x3 = 8
y1 = 8, y2 = 4 and y3 = 3
= [(5 + 2 + 8)/3, (8 + 4 + 3)/3]
= (15/3, 15/3)
= (5, 5)
So, the point which can balance the triangular plate is (5, 5).
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