(1) Using the functions f and g given below, find f o g and g o f . Check whether f o g = g o f .
(i) f(x) = x - 6, g(x) = x2 Solution
(ii) f(x) = 2/x, g(x) = 2x2 - 1 Solution
(iii) f(x) = (x + 6)/3, g(x) = 3 - x Solution
(iv) f(x) = 3 + x, g(x) = x - 4 Solution
(v) f(x) = 4x2 - 1, g(x) = 1 + x Solution
(2) Find the value of k, such that f o g = g o f
(i) f(x) = 3x + 2, g(x) = 6x - k Solution
(ii) f(x) = 2x - k, g(x) = 4x + 5 Solution
(3) If f(x) = 2x - 1, g(x) = (x + 1)/2, show that
f o g = g o f = x Solution
(4) (i) If f(x) = x2 - 1, g(x) = x - 2 find a, if g o f (a) = 1. Solution
(ii) Find k, if f(k) = 2k - 1 and f o f(k) = 5. Solution
(5) Let A, B, C ⊆ N and a function f : A -> B be defined by f(x) = 2x + 1 and g : B -> C be defined by g(x) = x2 . Find the range of f o g and g o f. Solution
(6) Let f(x) = x2 - 1 . Find (i) f o f (ii) f o f o f Solution
(7) If f : R -> R and g : R -> R are defined by f(x) = x5 and g(x) = x4 then check if f, g are one-one and f o g is one-one? Solution
(8) Consider the functions f(x), g(x), h(x) as given below. Show that (f o g) o h = f o (g o h) in each case.
(i) f(x) = x - 1, g(x) = 3x + 1 and h(x) = x2 Solution
(ii) f (x) = x2, g(x) = 2x and h(x) = x + 4 Solution
(iii) f (x) = x - 4, g(x) = x2 and h(x) = 3x - 5 Solution
(9) Let f = {(-1, 3),(0, -1),(2, -9)} be a linear function from Z into Z . Find f (x). Solution
(10) In electrical circuit theory, a circuit C(t) is called a linear circuit if it satisfies the superposition principle given by C(at1 + bt2) = aC(t1) + bC(t2), where a,b are constants. Show that the circuit C(t) = 3t is linear. Solution
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