A compound fraction is a fraction in which the numerator, the denominator, or both, are themselves fractional expressions.
Examples :
(1/a)/(b/2), (x + 1/y)/(y + 1/x)
Step 1 :
Simplify the numerator and the denominator of the complex fraction so that each is a single fraction.
Step 2 :
To divide the fraction in numerator by the fraction in denominator, invert the divisor and multiply.
Step 3 :
Simplify if possible.
Example 1 :
(2x/27y2)/(6x2/9)
Solution :
= (2x/27y2)/(6x2/9)
The numerator of the compound fraction is already a single fraction, and so is the denominator.
Invert the the fraction in denominator and multiply.
= (2x/27y2) ⋅ (9/6x2)
= (2x ⋅ 9) / (6x2 ⋅ 27y2)
Cancel common factors.
= 1 / (3x ⋅ 3y2)
= 1/9xy2
Example 2 :
(x/y + 1)/(1 - y/x)
Solution :
= (x/y + 1)/(1 - y/x)
We combine the terms in the numerator into a single fraction and do the same in the denominator. Then we invert and multiply.
= [(x + y)/y]/[(x - y)/x]
Invert the the fraction in denominator and multiply.
= [(x + y)/y)] ⋅ [x/(x - y)]
= [x(x + y)] / [y(x - y)]
Step 1 :
Find the least common denominator (LCD) of the fractions in both numerator and denominator of the compound fraction.
Step 2 :
Multiply the numerator and the denominator of the compound fraction by the LCD found in step 1.
Step 3 :
Simplify if possible.
Example 3 :
[5x/(x + 2)]/[10/(x - 2)]
Solution :
= [5x/(x + 2)]/[10/(x - 2)]
The least common denominator of the fractions in both numerator and denominator is (x + 2)(x - 2).
Multiply numerator and denominator by the LCD.
= [5x/(x + 2)](x + 2)(x - 2) / [10/(x - 2)](x + 2)(x - 2)
Simplify.
= [5x(x - 2)]/[10(x + 2)]
= x(x - 2)/2(x + 2)
Example 4 :
[x/y2 + 1/y] / [y/x2 + 1/x]
Solution :
= [x/y2 + 1/y] / [y/x2 + 1/x]
The least common denominator of the fractions in both numerator and denominator is x2y2.
Multiply numerator and denominator by the LCD.
= [x/y2 + 1/y](x2y2) / [y/x2 + 1/x](x2y2)
Use the distributive property.
= [x/y2 ⋅ x2y2 + 1/y ⋅ x2y2] / [y/x2 ⋅ x2y2 + 1/x ⋅ x2y2]
Simplify.
= [x3 + x2y]/[y3 + xy2]
Factor.
= [x2(x + y)]/[y2(y + x)]
= x2/y2
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