Consecutive Interior Angles :
If two lines are cut by a transversal, the pair of angles on the same side of the transversal and inside the two lines are called consecutive interior angles.
In the figure above, ∠4 and ∠5 are consecutive interior angles, and also ∠3 and ∠6 are consecutive angles.
Consecutive Interior Angles Theorem :
If two parallel lines are cut by a transversal, then the pairs of consecutive interior angles are supplementary.
Given : m||n, p is transversal.
Prove : ∠4 and ∠5 are supplementary and ∠3 and ∠6 are supplementary.
Statement m||n, p is transversal. |
Reason Given |
∠1 & ∠4 - linear pair ∠2 & ∠3 - linear pair |
Definition of linear pair |
∠1 & ∠4 - Supplementary m∠1 + m∠4 = 180° ∠2 & ∠3 - Supplementary m∠2 + m∠3 = 180° |
Supplementary Postulate |
∠1 ≅ ∠5 and ∠2 ≅ ∠6 |
Corresponding Angles Theorem |
∠4 & ∠5 - Supplementary ∠3 & ∠6 - Supplementary |
Substitution Property |
Problem 1 :
In the figure shown below, m∠3 = 105°. Find the measure of ∠6.
Solution :
In the figure above, lines m and n are parallel and p is transversal.
By Theorem, ∠3 and ∠6 are supplementary.
m∠3 + m∠6 = 180°
Substitute m∠3 = 105°.
105° + m∠6 = 180°
Subtract 105° from each side.
m∠6 = 75°
Problem 2 :
In the figure shown below, m∠3 = 102°. Find the measures ∠6, ∠12 and ∠13.
Solution :
In the figure above, lines m and n are parallel, p and q are parallel.
By Theorem, ∠3 and ∠6 are supplementary.
m∠3 + m∠6 = 180°
Substitute m∠3 = 102°.
102° + m∠6 = 180°
Subtract 102° from each side.
m∠6 = 78°
By Theorem, ∠3 and ∠12 are supplementary.
m∠3 + m∠12 = 180°
Substitute m∠3 = 102°.
102° + m∠12 = 180°
Subtract 102° from each side.
m∠12 = 78°
By Theorem, ∠12 and ∠13 are supplementary.
m∠12 + m∠13 = 180°
Substitute m∠12 = 78°.
78° + m∠13 = 180°
Subtract 78° from each side.
m∠13 = 102°
Therefore,
m∠6 = 78°
m∠12 = 78°
m∠13 = 102°
Problem 3 :
In the figure shown below, lines m and n are parallel and p is transversal. Find the value of x.
Solution :
In the figure above, lines m and n are parallel and p is transversal.
By Theorem, 5x° and (3x + 28)° are supplementary.
5x° + (3x + 28)° = 180°
5x + 3x + 28 = 180
8x + 28 = 180
Subtract 28 from each side.
8x = 152
Divide each side by 8.
x = 19
Problem 4 :
Using a 3rd parallel Line – Auxiliary Line, find the value of x.
Solution :
In the figure above, a° and 50° are corresponding angles and they are equal.
a° = 50°
By Theorem, b° and 100° are supplementary.
b° + 100° = 180°
Subtract 100° from each side.
b° = 80°
In the figure above,
x = a + b
= 50 + 80
= 130
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