DIGITAL SAT MATH PROBLEMS AND SOLUTIONS
(Part - 90)

Problem 1 :

A)  5

B)  10

C)  15

D)  20

Solution :

Problem 2 :

(xab)(xa) = 0

In the quadratic equation above, a and b are constants greater than zero. If 3 and 8 are two solutions to the equation, what is the value of b?

Solution :

Problem 3 :

If -4n + 7 > -12 and -4n – 7 < -12, what is one possible value of n?

Solution :

Problem 4 :

Let the function defined by f(x) = x2 - x + 3. If f(m + 1) = 5 and m is greater than 0, what is the value of m?

Solution :

Problem 5 :

When 2x2 - 5x + 3 is divided by 2x + 1, the result can be written as

where R is a constant. What is the value of R?

Solution :

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