Equation of the line containing the point and slope :
(y - y1) = m(x - x1)
Equation of the line containing two points :
(y - y1)/(y2 - y1) = (x - x1)/(x - x1)
Example 1 :
Find the equation of the line in the xy-plane with slope −4 that contains the point (−5,−2).
Solution :
(y - y1) = m(x - x1)
(x1, y1) ==> (-5, -2) and m = -4
(y - (-2)) = -4(x - (-5))
(y + 2) = -4(x + 5)
y + 2 = -4x - 20
4x + y + 2 + 20 = 0
4x + y + 22 = 0
Example 2 :
Find the equation of the line that contains the points (2,−1) and (4, 9).
Solution :
(y - y1)/(y2 - y1) = (x - x1)/(x - x1)
(y + 1)/(9 + 1) = (x - 2)/(4 - 2)
(y + 1)/10 = (x - 2)/2
2(y + 1) = 10(x - 2)
2y + 2 = 10x - 20
10x - 2y - 20 - 2 = 0
10x - 2y - 22 = 0
5x - y - 11 = 0
Example 3 :
Find the equation of the line that contains the points (−3, 2) and (−5, 7).
Solution :
(y - y1)/(y2 - y1) = (x - x1)/(x - x1)
(y - 2)/(7 - 2) = (x + 3)/(-5 + 3)
(y - 2)/5 = (x + 3)/(-2)
-2(y - 2) = 5(x + 3)
-2y + 4 = 5x + 15
5x + 2y + 15 - 4 = 0
5x + 2y + 11 = 0
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