Write the equivalent algebraic expressions for the following :
Question 1 :
7(x - 3) + 2(2x - 5) - 3(x - 5)
Question 2 :
4x - (2 + 4x) - 2(x - 1) - 8(x -3)
Question 3 :
(x + 3)2 - (x - 3)2
Question 4 :
Question 5 :
Question 6 :
Question 7 :
Question 8 :
Question 9 :
Question 10 :
Question 11 :
Which of the following expressions is equivalent to 6x - 3 for all real values of x?
(A) 2(3x - 3)
(B) 3(2x - 3)
(C) 2(3x + 1) - 5
(D) 6(x - 3)
(E) 6(x - 1) - 1
Question 12 :
If (x + 3)(x + a) = x2 + bx + 6, find the value of 'a' and 'b'.
1. Answer :
= 7(x - 3) + 2(2x - 5) - 3(x - 5)
Use Distributive Property.
= 7(x) + 7(-3) + 2(2x) + 2(-5) - 3(x) - 3(-5)
= 7x - 21 + 4x - 10 - 3x + 15
= 8x - 16
2. Answer :
= 4x - (2 + 4x) - 2(x - 1) - 8(x -3)
Use Distributive Property.
= 4x - 2 - 4x - 2(x) - 2(-1) - 8(x) - 8(-3)
= 4x - 2 - 4x - 2x + 2 - 8x + 24
= -10x + 24
3. Answer :
= (x + 3)2 - (x - 3)2
= (x + 3)(x + 3) - (x - 3)(x - 3)
= (x2 + 3x + 3x + 9) - (x2 - 3x - 3x + 9)
= (x2 + 6x + 9) - (x2 - 6x + 9)
= x2 + 6x + 9 - x2 + 6x - 9
= 12x
4. Answer :
5. Answer :
6. Answer :
7. Answer :
8. Answer :
9. Answer :
10. Answer :
11. Answer :
Given expression : 6x - 3.
Options :
(A) 2(3x - 3)
(B) 3(2x - 3)
(C) 2(3x + 1) - 5
(D) 6(x - 3)
(E) 6(x - 1) - 1
In the given expression, the coefficient of x is 6 and constant is -3.
In all the above options, the coefficient of x is 6. We have to find the option in which the constant is -3.
When you simplify the expression in option (C), the constant is -3.
Option (C) :
2(3x + 1) - 5 = 2(3x) + 2(1) - 5
= 6x + 2 - 5
= 6x - 3
So, the correct choice is option (C).
12. Answer :
(x + 3)(x + a) = x2 + bx + 6
x2 + ax + 3x + 3a = x2 + bx + 6
x2 + (a + 3)x + 3a = x2 + bx + 6
Since the above two expressions are equal, coefficients of like terms also must be equal.
Equate the coefficients of x and constants.
a + 3 = b or b = a + 3 ----(1) |
3a = 6 a = 3 |
Substitute a = 3 in (1).
b = 3 + 3
b = 6
Therefore,
a = 3 and b = 6
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