EVALUATE POLYNOMIALS USING SYNTHETIC DIVISION

An elegant way of dividing a polynomial by a linear  polynomial was introduced by Paolo Ruffin in 1809. His method is known as synthetic division. It facilitates the division of a polynomial by a linear polynomial with the help of the coefficients involved.

Let us see how synthetic division can be used to explain the method of synthetic division with an example.

Let p(x) = x3 + 2x2 - x - 4 be the dividend and q(x) = x + 2 be the divisor. We shall find the quotient s(x) and the remainder r, by proceeding as follows.

Step 1 :

Arrange the dividend and the divisor according to the descending powers of x and then write the coefficients of dividend in the first row (see figure). Insert 0 for missing terms.

Step 2 :

Find out the zero of the divisor.

x + 2 = 0

x = -2

Step 2 :

Put 0 for the first entry in the 2nd row.

Complete the entries of the 2nd row and 3rd row as shown below.

Step 4 :

Write down the quotient and the remainder accordingly. All the entries except the last one in the third row constitute the coefficients of the quotient.

Thus, the quotient is x2 - 1 and the remainder is –2.

In the above synthetic division. zero of the divisor is -2 and the remainder is -2.

This can be written as

p(-2) = -2

When we substitute the zero of the divisor -2 for x into p(x), the result is the remainder -2.

That is, evaluation of the polynomial p(x) for x = -2 is -2.

Example 1 :

If f(x) = x3 + x2 - 7x - 3, then evaluate f(3).

Solution :

From the synthetic division above, we have

f(3) = 12

Example 2 :

If g(x) = 2x3 - 3x2 - 3x + 2, then evaluate g(-1).

Solution :

From the synthetic division above, we have

g(-1) = 0

Example 3 :

If p(x) = x3 - 3x2 - 10x + 24, then evaluate p(2).

Solution :

From the synthetic division above, we have

p(2) = 0

Example 4 :

If q(x) = 2x4 + x3 - 14x2 - 19x + 6, then evaluate q(-1/2).

Solution :

From the synthetic division above, we have

q(-1/2) = 12

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