Evaluate each of the following logarithmic expressions :
Problem 1 :
log2 24 - log2 3
Problem 2 :
log3 27 + log3 729
Problem 3 :
log10 8 + log10 5 - log10 4
Problem 4 :
log7 98 - log7 14 + log7 343
Problem 5 :
Problem 6 :
log 50 - (log 25 + log 2)
Problem 7 :
log2 2 + log2 3 - log2 6 - log2 8
Problem 8 :
4log2 2 + log3 27 - 3log2 2 - log2 81
Problem 9 :
log3 2 ⋅ log4 3 ⋅ log5 4 ⋅ log6 5 ⋅ log7 6 ⋅ log8 7
Problem 10 :
log7 21 + log7 77 + log7 88 - log7 121 - log7 24
Problem 11 :
Problem 12 :
5log10 2 + 2log10 3 - 6log64 4
Problem 13 :
1. Answer :
= log2 24 - log2 3
= log2 8
= log2 23
= 3log2 2
= 3(1)
= 3
2. Answer :
= log3 27 + log3 729
= log3 33 + log3 36
= 3log3 3 + 6log3 3
= 3(1) + 6(1)
= 3 + 6
= 9
3. Answer :
= log10 8 + log10 5 - log10 4
= log10 (8 ⋅ 5) - log10 4
= = log10 40 - log10 4
= log10 10
= 1
4`. Answer :
= log7 98 - log7 14 + log7 343
= log7 7 + log7 73
= 1 + 3log7 7
= 1 + 3(1)
= 1 + 3
= 4
5. Answer :
6. Answer :
= log 50 - (log 25 + log 2)
= log 50 - log (25 ⋅ 2)
= log 50 - log 50
= 0
7. Answer :
= log2 2 + log2 3 - log2 6 - log2 8
= (log2 2 + log2 3) - (log2 6 + log2 8)
= log2 (2 ⋅ 3) - log2 (6 ⋅ 8)
= log2 6 - log2 48
= log2 2-3
= -3log2 2
= -3(1)
= -3
8. Answer :
= 4log2 2 + log3 27 - 3log2 2 - log3 81
= 4(1) + log3 33 - 3(1) - log3 34
= 4 + 3log3 3 - 3 - 4log3 3
= 4 + 3(1) - 3 - 4(1)
= 4 + 3 - 3 - 4
= 0
9. Answer :
= log32 ⋅ log43 ⋅ log54 ⋅ log65 ⋅ log76 ⋅ log87
In the above expression, logarithms have differemnt bases. Group the logarithms with the same base and simplify.
= (log3 2 ⋅ log4 3) ⋅ (log5 4 ⋅ log6 5) ⋅ (log7 6 ⋅ log8 7)
= log4 2 ⋅ log6 4 ⋅ log8 6
= log6 2 ⋅ log8 6
= log8 2
10. Answer :
= log7 21 + log7 77 + log7 88 - log7 121 - log7 24
= log7 (21 ⋅ 77 ⋅ 88) - (log7 121 + log7 24)
= log7 (21 ⋅ 77 ⋅ 88) - log7 (121 ⋅ 24)
= log7 142296 - log7 2904
= log7 49
= log7 72
= 2log7 7
= 2(1)
= 2
11. Answer :
= log8 64
= log8 82
= 2log8 8
= 2(1)
= 2
12. Answer :
= 5log10 2 + 2log10 3 - 6log64 4
= 5log10 2 + 2log10 3 - (2 ⋅ 3)log64 4
= log10 25 + log10 32 - 2log64 43
= log10 32 + log10 9 - 2log64 64
= log10 32 + log10 9 - 2(1)
= log10 32 + log10 9 - 2log10 10
= log10 (32 ⋅ 9) - log10 102
= log10 288 - log10 100
13. Answer :
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