Law 1 :
Logarithm of product of two numbers is equal to the sum of the logarithms of the numbers to the same base.
That is,
logamn = logam + logan
Law 2 :
Logarithm of the quotient of two numbers is equal to the difference of their logarithms to the same base.
That is,
loga(m/n) = logam - logan
Law 3 :
Logarithm of a number raised to a power is equal to the power multiplied by the logarithm of the number to the same base.
That is,
logamn = nlogam
Change of Base :
logba = logxa ⋅ logbx
logba = logxa / logxb
Example 1 :
Evaluate :
log327 + log3729
Solution :
= log327 + log3729
= log333 + log336
= 3log33 + 6log33
= 3(1) + 6(1)
= 3 + 6
= 9
Example 2 :
Simplify :
log108 + log105 - log104
Solution :
= log108 + log105 - log104
= log10 (8 ⋅ 5)/4]
= log1010
= 1
Example 3 :
Evaluate :
log798 - log714 + log7343
Solution :
= log798 - log714 + log7343
= log7(98/14) + log7343
= log77 + log773
= 1 + 3log77
= 1 + 3(1)
= 1 + 3
= 4
Example 4 :
Evaluate :
(1/2)log936 + 2log94 - 3log94
Solution :
= (1/2)log936 + 2log94 - 3log94
= log9(36)1/2 + log942 - log943
= log9√36 + log916 - log964
= log96 + log916 - log964
= log9(6 ⋅ 16) - log964
= log996 - log964
= log9(96/64)
= log9(3/2)
Example 5 :
Simplify :
log32 ⋅ log43 ⋅ log54 ⋅ log65 ⋅ log76 ⋅ log87
Solution :
In the given expression, logarithms have bases.
First group the logarithms with the same base and simplify.
= (log32 ⋅ log43) ⋅ (log54 ⋅ log65) ⋅ (log76 ⋅ log87)
= log42 ⋅ log64 ⋅ log86
= log62 ⋅ log86
= log82
= 1/log28
= 1/log223
= 1/3(log22)
= 1/3(1)
= 1/3
Example 6 :
Simplify :
log721 + log777 + log788 - log7121 - log724
Solution :
= log721 + log777 + log788 - log7121 - log724
= log7(21 ⋅ 77 ⋅ 88) - (log7121 + log724)
= log7(21 ⋅ 77 ⋅ 88) - log7(121 ⋅ 24)
= log7 142296 - log72904
= log7(142296 / 2904)
= log749
= log772
= 2log77
= 2(1)
= 2
Example 7 :
Simplify :
log816 + log852 - 1/log138
Solution :
= log816 + log852 - 1/log138
= log816 + log852 - log813
= log8[(16 ⋅ 52)/13]
= log8(16 ⋅ 4)
= log864
= log882
= 2log88
= 2(1)
= 2
Example 8 :
Simplify :
5log102 + 2log103 - 6log644
Solution :
= 5log102 + 2log103 - (2⋅3) log644
= log1025 + log1032 - 2log6443
= log1032 + log109 - 2log6464
= log1032 + log109 - 2(1)
= log1032 + log109 - 2log1010
= log10(32 ⋅ 9) - log10102
= log10288 - log10100
= log10(288/100)
= log10(72/25)
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