Evaluating real world expressions :
An algebraic expression is an expression that contains one or more variables and may also contain operation symbols, such as + or -
We can solve many real world problems by evaluating algebraic expressions.
Example 1 :
A scientist measures the air temperature in Death Valley, California, and records 50 °C. The expression
1.8c + 32
gives the temperature in degrees Fahrenheit for a given temperature in degrees Celsius c. Find the temperature in degrees Fahrenheit that is equivalent to 50 °C.
Solution :
Step 1 :
Fromm the given information, we have
c = 50 °C
Step 2 :
Plug the value into the expression.
1.8c + 32
Plug 50 for c
1.8(50) + 32
Multiply
90 + 32
Add
122
Hence, 122 °F is equivalent to 50 °C.
Example 2 :
The expression 6x² gives the surface area of a cube, where x is the length of one side of the cube. Find the surface area of a cube with a side length of 2 meters.
Solution :
Step 1 :
Fromm the given information, we have
x = 2
Step 2 :
Plug the value into the expression which represents surface area of the cube.
6x²
Plug 2 for x
6(2)²
Evaluate exponents
6(4)
Multiply
24
Hence, the surface area of the cube 24 m²
Example 3 :
The expression x³ gives the volume of a cube, where x is the length of one side of the cube. Find the volume of a cube with a side length of 2 meters.
Solution :
Step 1 :
Fromm the given information, we have
x = 2
Step 2 :
Plug the value into the expression.
x³
Plug 2 for x
(2)³
Evaluate exponents
8
Hence, the volume of the cube 8 m3
Example 4 :
The expression 60m gives the number of seconds in m minutes. How many seconds are there in 7 minutes?
Solution :
Step 1 :
Fromm the given information, we have
m = 7
Step 2 :
Plug the value into the expression.
60m
Plug 7 for m
60(7)
Multiply
420
Hence, there are 420 seconds in 7 minutes.
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