Problem 1 :
Evaluate the following expression when x = 3 and y = 2.
x2y3
Problem 2 :
Evaluate the following expression when x = 4 and y = 2.
x2/y3
Problem 3 :
If 42n + 3 = 8n + 5, then find the value of n.
Problem 4 :
If 2x/2y = 23, then find the value x in terms of y.
Problem 5 :
If ax = b, by = c and cz = a, then find the value of xyz.
Problem 6 :
If k(2x) = 2x+3 - 2x, then solve for k.
Problem 7 :
Evaluate :
3√-8
Problem 8 :
Evaluate :
√64 + √196
Problem 9 :
(√3)3 + √27
Problem 10 :
Solve for x :
1/3√x = 2
Problem 11 :
Simplify :
3√(x6y9)
Problem 12 :
Solve for x :
√(x3 + 56) = 8
1. Solution :
= x2y3
Substitute x = 3 and y = 2.
= (3)2(2)3
= (3 ⋅ 3)(2 ⋅ 2 ⋅ 2)
= (9)(8)
= 72
2. Solution :
= x2/y3
Substitute x = 4 and y = 2.
= 42/23
= (4 ⋅ 4)/(2 ⋅ 2 ⋅ 2)
= 16/8
= 2
3. Solution :
42n + 3 = 8n + 5
(22)2n + 3 = (23)n + 5
22(2n + 3) = 23(n + 5)
Equate the exponents.
2(2n + 3) = 3(n + 5)
4n + 6 = 3n + 15
n = 9
4. Solution :
2x/2y = 23
2x - y = 23
x - y = 3
Add y to both sides.
x = y + 3
5. Solution :
Given : ax = b, by = c and cz = a.
ax = b
Substitute a = cz.
(cz)x = b
czx = b
Substitute c = by.
(by)zx = b
bxyz = b
bxyz = b1
xyz = 1
6. Solution :
k(2x) = 2x+3 - 2x
Using laws of exponents, we have
k(2x) = 2x ⋅ 23 - 2x
k(2x) = 2x ⋅ 8 - 2x
k(2x) = 2x(8 - 1)
k(2x) = 2x(7)
Divide each side by 2x.
k = 7
7. Solution :
3√-8 = 3√(-2 ⋅ -2 ⋅ -2)
= -2
8. Solution :
√64 + √196
Because 64 and 196 are perfect squares, we can find the square root of 64 and 194 as shown below.
√64 = √(8 ⋅ 8) √64 = 8 |
√196 = √(14 ⋅ 14) √196 = 14 |
√64 + √196 = 8 + 14
= 22
9. Answer :
(√3)3 + √27 = (√3 ⋅ √3 ⋅ √3) + √(3 ⋅ 3 ⋅ 3)
= (3 ⋅ √3) + 3√3
= 3√3 + 3√3
10. Solution :
1/3√x = 2
1/x1/3 = 2
x-1/3 = 2
x = 2-3
x = 1/23
x = 1/8
11. Solution :
= 3√(x6y9)
= (x6y9)1/3
= (x6)1/3(y9)1/3
= x6/3y9/3
= x2y3
12. Solution :
√(x3 + 56) = 8
Take square on both sides.
[√(x3 + 56)]2 = 82
x3 + 56 = 64
Subtract 56 from both sides.
x3 = 8
x3 = 23
x = 2
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