Monomial is an algebraic expression consisting of one term. Factoring monomials is a process of breaking down a monomial into smaller terms. Even though factoring a polynomial usually shortens the polynomial, factoring a monomial expands it.
Write the prime factorization of each monomial in the following examples. Do not use exponents.
Example 1 :
25n2
Solution :
25n2 = 5 ⋅ 5 ⋅ n ⋅ n
Example 2 :
18xy
Solution :
18xy = 2 ⋅ 3 ⋅ 3 ⋅ x ⋅ y
Example 3 :
12y
Solution :
12y = 2 ⋅ 2 ⋅ 3 ⋅ y
Example 4 :
21y2
Solution :
21y2 = 3 ⋅ 7 ⋅ y ⋅ y
Example 5 :
81a
Solution :
81a = 3 ⋅ 3 ⋅ 3 ⋅ 3 ⋅ a
Example 6 :
92q
Solution :
92q = 2 ⋅ 2 ⋅ 23 ⋅ q
Example 7 :
36x3
Solution :
36x3 = 2 ⋅ 2 ⋅ 3 ⋅ 3 ⋅ x ⋅ x ⋅ x
Example 8 :
24h
Solution :
24h = 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ h
Example 9 :
48x2
Solution :
48x2 = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ x ⋅ x
Example 10 :
x2y3
Solution :
x2y3 = x ⋅ x ⋅ y ⋅ y ⋅ y
Factor monomial from the following polynomials.
Example 11 :
9a2 - 18a
Solution :
= 9a2 - 18a
Factoring 9a, we get
= 9a(a) - 2(9a)
= 9 a (a - 2)
Example 12 :
x3 - 5x2
Solution :
= x3 - 5x2
Factoring the monomial x2, we get
= x2 (x - 5)
Example 13 :
9x2 - 36
Solution :
= 9x2 - 36
= 9x2 - 4(9)
Factoring 9, we get
= 9(x2 - 4)
Here 4 can be written as 22
= 9(x2 - 22)
Here x2 - 22 looks like a2 - b2 = (a + b)(a - b)
= 9 (x + 2)(x - 2)
Example 14 :
8x2 + 72x
Solution :
= 8x2 + 72x
Writing 72 as a product of 8.
= 8x2 + 8(9)x
= 8 x(x + 9)
Example 15 :
8x2 - 80x
Solution :
= 8x2 - 80x
Writing 80 as a product of 8.
= 8x2 - 8(10)x
= 8 x (x - 10)
Example 16 :
16a5b3 + 32a4
Solution :
= 16a5b3 + 32a4
= 16a5b3 + 16a4 (2)
= 16a4(ab3 + 2)
Example 17 :
11m2 - 99m
Solution :
= 11m2 - 99m
= 11m2 - 11m (9)
= 11m (m - 9)
Example 18 :
x2 + x3 + x4
Solution :
= x2 + x3 + x4
Factoring x2, we get
= x2 (1 + x + x2 )
Example 19 :
36x3 / 42 x2
Solution :
= 36x3 / 42 x2
Both 36 and 42 are multiples of 6 and x2 is in common. By factoring 6 x2 from the numerator and denominator, we get
= 6x2 (6x) / 6 x2 (7)
Cancelling the common factor, we get
= 6x/7
Example 20 :
16p2 / 28 p
Solution :
= 16p2 / 28 p
Both 16 and 28 are multiples of 4 and p is in common. By factoring 4p from the numerator and denominator, we get
= 4p(4p) / 4p (7)
Cancelling the common factor, we get
= 4p/7
Example 21 :
32n2 / 24n
Solution :
= 32n2 / 24n
Both 32 and 24 are multiples of 8 and n is in common. By factoring 8n from the numerator and denominator, we get
= 8n(4n) / 8n (3)
Cancelling the common factor, we get
= 4n/3
Example 22 :
70n2 / 28n
Solution :
= 70n2 / 28n
Both 70 and 28 are multiples of 7 and n is in common. By factoring 7n from the numerator and denominator, we get
= 7n(10n) / 7n (4)
Cancelling the common factor, we get
= 10n/4
= 2(5n)/2(2)
= 5n/2
Example 23 :
(2r - 4) / (r - 2)
Solution :
= (2r - 4) / (r - 2)
= (2r - 2(2)) / (r - 2)
= 2(r - 2) / (r - 2)
Cancelling common factor, we get
= 2
Example 24 :
45/(10a - 25)
Solution :
= 45/(10a - 25)
In the denominator 10 and 25 are multiples of 5. Factoring 5, we get
= 5(9)/(2⋅5a - 5⋅5)
= 5(9)/5(2a - 5)
= 9/(2a - 5)
Example 25 :
(15 a - 3)/24
Solution :
= (15 a - 3)/24
In the numerator 15 and 3 are multiples of 3. Factoring 3, we get
= (5⋅3 a - 3)/24
= 3(5 a - 1)/24
= (5a - 1)/8
Example 26 :
(x - 4)/(3x2 - 12x)
Solution :
= (x - 4)/(3x2 - 12x)
In the denominator, both 3x2 and 12x can be expressed as a product of 3x.
= (x - 4)/3x(x - 4)
Cancelling common factor, we get
= 1/3x
Example 27 :
27/(27x + 18)
Solution :
= 27/(27x + 18)
In the denominator 27 and 18 are the multiples of 9.
= 27/(3⋅9x + 2⋅9)
= 27/9(3x + 2)
Here 27 and 9 can be simplified using 9 times table.
= 3/(3x + 2)
Example 28 :
(4x - 4) / (6x - 20)
Solution :
= (4x - 4) / (6x - 20)
Factoring 4 from the numerator and factoring 2 from the denominator, we get
= 4(x - 1) / 2(3x - 10)
= 2(x - 1)/(3x - 10)
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