Factor each of the following polynomials using synthetic division :
1) x3 - 3x2 - 10x + 24
2) 2x3 - 3x2 - 3x + 2
3) -7x + 3 + 4x3
4) x3 + x2 - 14x - 24
5) x3 - 7x + 6
6) x3 - 10x2 - x + 10
1. Answer :
x3 - 3x2 - 10x + 24
By Substituting x = 2, we get the remainder 0.
So (x - 2) is a factor.
Then,
x2 - x - 12 = x2 - 4x + 3x - 12
x2 - x - 12 = x(x - 4) + 3(x - 4)
x2 - x - 12 = (x + 3)(x - 4)
Therefore, the factors are (x - 2)(x + 3)(x- 4).
2. Answer :
2x3 - 3x2 - 3x + 2
By substituting x = -1, we get the remainder 0.
So (x + 1) is a factor.
Then,
2x2 - 5x + 2 = 2x2 - 4x - x + 2
2x2 - 5x + 2 = 2x(x - 2) - 1(x - 2)
2x2 - 5x + 2 = (2x - 1)(x - 2)
Therefore, the factors are (x + 1)(2x - 1)(x - 2).
3. Answer :
-7x + 3 + 4x3
-7x + 3 + 4x3 = 4x3 + 0x2 - 7x + 3
By substituting x = 1, we get the remainder 0.
So (x - 1) is a factor.
Then,
4x2 + 4x - 3 = 4x2 + 6x - 2x - 3
4x2 + 4x - 3 = 2x(2x + 3) - 1(2x + 3)
4x2 + 4x - 3 = (2x - 1)(2x + 3)
Therefore, the factors are (x - 1)(2x - 1)(2x + 3).
4. Answer :
x3 + x2 - 14x - 24
By substituting x = -2, we get the remainder 0.
So (x + 2) is a factor.
Then,
x2 - x - 12 = x2 - 4x + 3x - 12
x2 - x - 12 = x(x - 4) + 3(x - 4)
x2 - x - 12 = (x + 3)(x - 4)
Therefore, the factors are (x + 2)(x + 3)(x - 4).
5. Answer :
x3 - 7x + 6
By substituting x = 1, we get the remainder 0.
So (x - 1) is a factor.
Then,
x2 + x - 6 = x2 + 3x - 2x - 6
x2 + x - 6 = x(x + 3) - 2(x + 3)
x2 + x - 6 = (x + 3)(x - 2)
Therefore, the factors are (x - 2)(x + 3)(x - 1).
6. Answer :
x3 - 10x2 - x + 10
By substituting x = 1, we get the remainder 0.
So (x - 1) is a factor.
Then,
x2 - 9x - 10 = x2 - 10x + 1x - 10
x2 - 9x - 10 = x(x - 10) + 1(x - 10)
x2 - 9x - 10 = (x + 1)(x - 10)
Therefore, the factors are (x + 1)(x - 10)(x - 1).
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