From the given rule and output to find the sequence, we have to follow the steps given below.
(1) Assume x as input and y as output
(2) Based on the rule given find the function
(3) Apply the given input or output values in the function and find the other one.
Given the following output numbers and rules, calculate the corresponding input numbers :
Example 1 :
Rule : the input number plus four
Output numbers {5, 7, 15}
Solution :
Let x and y be the input and output number respectively.
y = 5 5 = x+4 x = 5-4 x = 1 1 ==> 5 |
y = 7 7 = x+4 x = 7-4 x = 3 1 ==> 3 |
y = 15 15 = x + 4 15 – 4 = x x = 11 11 ==> 15 |
So, the required function is y = x+4
So, input numbers and output numbers are
1 ==> 5, 3 ==> 7, 11 ==> 15
Example 2 :
Double the input number plus two
Output numbers {2, 4, 10}
Solution :
Let x and y be input and output respectively.
So, the required function is y = 2x+2
y = 2 2 = 2x + 2 x = 0 0 ==> 2 |
y = 4 4 = 2x + 2 x = 1 1 ==> 4 |
y = 10 10 = 2x + 2 x = 4 4 ==> 10 |
So, input numbers and output numbers are
0 ==> 2, 1 ==> 4, 4 ==> 10
Example 3 :
Rule : Five times the input number minus three
Output numbers {7, 12, 17}
Solution :
Let x and y be input and output respectively.
So, the required function is y = 5x-3
y = 7 7 = 5x - 3 x = 2 7 ==> 2 |
y = 12 12 = 5x - 3 x = 3 3 ==> 12 |
y = 17 17 = 5x - 3 x = 4 4 ==> 17 |
So, input numbers and output numbers are
7 ==> 2, 3 ==> 12, 4 ==> 17
Example 4 :
Rule : Add one to the input number then double the result
Output numbers {2, 6, 12}
Solution :
Let x and y be input and output respectively.
Add one to the input number ==> x+1
double the result ==> 2(x+1)
y = 2 2 = 2x + 2 x = 0 0 ==> 2 |
y = 6 6 = 2x + 2 x = 2 2 ==> 6 |
y = 12 12 = 2x + 2 x = 5 5 ==> 12 |
So, input numbers and output numbers are
0 ==> 2, 2 ==> 6, 5 ==> 12
Example 5 :
Rule : Multiply the input number by itself then add one
Output numbers : {2, 5, 17}
Solution :
Let x and y be input and output respectively.
Multiply the input number by itself = x(x)
= x2
add one = x2 +1
y = 2 2 = x2 + 1 x2 = 1 x = ±1 ±1 ==> 2 |
y = 5 5 = x2 + 1 x2 = 4 x = ±2 ±2 ==> 5 |
y = 17 17 = x2 + 1 x2 = 16 x = ±4 ±4 ==> 17 |
Example 6 :
Rule : Multiply the input number by one more
than itself.
Output numbers {2, 6, 20}
Solution :
Let x and y be input and output respectively.
According to
given rule,
y = x(x+1)
y = x2 + x
when y = 2
2 = x2 + x
x2 + x – 2 = 0
(x – 1) (x + 2) = 0
x = 1, -2
1 and -2 ==> 2
when y = 6
6 = x2 + x
x2 + x – 6 = 0
(x + 3) (x – 2) = 0
x = 2, -3
2 and -3 ==> 6
when y = 20
20 = x2 + x
20 = x2 + x
x2 + x – 20 = 0
(x + 5) (x – 4) = 0
x = 4, -5
4 and -5 ==> 20
So, input numbers and output numbers are
1 and -2 ==> 2, 2 and -3 ==> 6 and 4 and -5 ==> 20
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