To find inverse function of the given function, we follow the steps given below.
Step 1 :
Let the given function be f(x). The given function will be defined in terms of x. Replace f(x) by y.
Step 2 :
In the given function interchange y and x.
Step 3 :
Derive the new equation for y.
Step 4 :
y can be replaced by f-1(x)
For each of the following functions :
Example 1 :
a) f(x) = 2x+5 b) f(x) = (3-2x)/4 c) f(x) = x+3
(i) Find f-1(x)
(ii) sketch y = f(x), y = f-1(x) and y = x on the same axes.
Solution :
a) f(x) = 2x+5
(i)
Step 1 :
Let, y = f(x)
y = 2x+5
Step 2 :
By interchanging x and y, we get
x = 2y+5
2y = x-5
y = (x-5)/2
Step 3 :
So, the required inverse function is
f-1(x) = (x-5)/2
(ii) By applying some random values of x in the function
y = 2x+5
![]() |
By joining the points (-1, 3), (0, 5) and (1, 7), we will get the graph of original function. So, the required coordinates of inverse function are (3,-1) (5, 0) and (7, 1). |
We draw the graph of inverse function be reflecting the graph of original function about y = x.
b) f(x) = (3-2x)/4
Solution :
(i) Let, y = f(x)
y = (3-2x)/4
By interchanging x and y, we get
x = (3-2y)/4
4x = 3-2y
2y = 3-4x
y
= (3-4x)/2
y = -2x+(3/2)
We express f-1 as a function of x in terms of y
f-1(x) = -2x+(3/2)
(ii) For graphing, by applying some random values of x in the function
y = -2x+(3/2)
![]() |
By joining the points (-1, 5/4), (0, 3/4) and (1, 1/4), we will get the graph of original function. So, the required coordinates of inverse function are (5/4, -1), (3/4, 0) and (1/4, 1) |
By plotting the points, we get graph of the given function and inverse function.
c) f(x) = x+3
Solution :
(i) Let, y = f(x)
y = x+3
By interchanging x and y, we get
x = y+3
y = x-3
We express f-1 as a function of x in terms of y
f-1(x) = x-3
(ii)
![]() |
Coordinates of given function : (-1, -4) (0, -3) and (1, -2) Coordinates of inverse function : (-4, -1) (-3, 0) and (-2, 1) |
Example 2 :
If f(x) = 2x + 7, find :
a) f-1(x) b) f(f-1(x)) c) f-1(f(x))
Solution :
a.
Given, f(x) = 2x + 7
Let y = 2x+7
By interchanging x and y, we get
x = 2y+7
2y = x-7
y
= (x-7)/2
We express f-1 as a function of x in terms of y
f-1(x) = (x-7)/2
b)
We have, f-1(x) = (x-7)/2
Then,
f(f-1(x)) = f((x-7)/2)
= 2x+7
= 2[(x-7)/2] + 7
= x–7+7
f(f-1(x)) = x ----(1)
c)
we have, f-1(x) = (x-7)/2
f-1(f(x)) = (f(x) - 7)/2
= (2x+7-7)/2
= 2x/2
f-1(f(x)) = x ----(2)
Example 3 :
If f(x) = (2x + 1)/(x + 3), find :
a) f-1(x) b) f(f-1(x)) c) f-1(f(x))
Solution :
a)
Given, f(x) = (2x+1)/(x+3)
Let y = (2x+1)/(x+3)
By interchanging x and y, we get
x = (2y+1)/(y+3)
x(y+3) = 2y+1
xy+3x = 2y+1
-2y+xy = -3x+1
y(-2+x) = -3x+1
y = (-3x+1)/(x-2)
y = (1-3x)/(x-2)
We express f-1 as a function of x in terms of y
f-1(x) = (1-3x)/(x-2)
b) f(f-1(x)) = f((1-3x)/(x-2))
By using x in terms of f(x), we get
f(x) = (2x+1)/(x+3)
= [2[(1-3x)/(x-2)]+1]/[(1-3x)/(x-2)+3]
= [(2-6x+x-2)/(x-2)]/[(1-3x+3x-6)/(x-2)]
= (-5x)/(-5)
= x
f(f-1(x)) = x ------(1)
c) we have, f-1(x) = (1-3x)/(x-2)
By using f(x) in terms of f-1(x), we get
f-1(f(x)) = (1-3f(x))/(f(x)-2)
simplifying the terms,
= [1-3(2x+1)/(x+3)]/[(2x+1)/(x+3)-2)
= [(x+3) – 3(2x+1)/(x+3)]/[(2x+1) – 2(x+3)/(x+3)]
= [x+3–6x–3]/[2x+1–2x–6]
= (-5x)/(-5)
= x
f-1(f(x)) = x ------(2)
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