The sine law is a relationship between the sides and angles in any triangle.
Let ABC be any triangle, where a, b, and c represent the measures of the sides opposite to the angle measures ∠A, ∠B, and ∠C, respectively.
Then,
a/sin A = b/sin B = c/sin C
(or)
sin A/a = sin B/b = sin C/c
Example 1 :
Determine the value of the marked unknown angle in each.
Solution :
(a) From the picture given above, we know that we need to find the angle C.
BC = a, AC = b = 31 m and AB = c = 28 m
<B = 62
a/sin A = b/sin B = c/sin C
31/sin 62 = 28/sin C
31/0.8829 = 28/sin C
35.11 = 28/sin C
sin C = 28/35.11
sin C = 0.7974
C = 52.88°
Hence the required angle is 53° (approximately).
(b) BC = a = 15, AC = b = 17.5 m and AB = c
<B = 98, <A = ?
a/sin A = b/sin B = c/sin C
15/sin A = 17.5/sin 98
15/sin A = 17.5/0.9902
15/sin A = 17.67
sin A = 15/17.67
sin A = 0.8488
Hence the required angle is 58° (approximately).
Example 2 :
Determining the lengths of all three sides and the measures of all three angles is called solving a triangle. Solve each triangle
Solution :
(a) AB = c = 13 m, BC = a, AC = b = 12 m
<B = 67
a/sin A = b/sin B = c/sin C ----(1)
a/sin A = 12/sin 67 = 13/sin C
12/sin 67 = 13/sin C
12/0.9205 = 13/sin C
13.03 = 13/sin C
sin C = 13/13.03
sin C = 0.9976
<C = 86
In triangle ABC,
<A + <B + <C = 180
<A + 67 + 86 = 180
<A + 153 = 180
<A = 180 - 153
<A = 27
a/sin 27 = 12/sin 67 = 13/sin 86
a/sin 27 = 12/sin 67
a/0.4539 = 13.03
a = 13.03(0.4539)
a = 5.91 approximately 6 m
Hence the missing side and missing angles are 6 m and 86 respectively.
(b) AB = c, BC = a, AC = b = 50 m
<A = 42, <B = 84
a/sin A = b/sin B = c/sin C
a/sin 42 = 50/sin 84 = c/sin C
a/sin 42 = 50/sin 84
a/0.6691 = 50/0.9945
a = 50.27 (0.6691)
a = 33.63 approximately 33.6 m
In triangle ABC,
<A + <B + <C = 180
42 + 84 + <C = 180
<C = 180 - 126
<C = 54
So, the missing side and missing angle are 33.6 m and 54 degree.
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