Find the quotient and remainder of the following.
Example 1 :
(10 + 7x + x2) ÷ (x + 2)
Solution :
Let us first write the degree of each polynomial in descending order.
Given, (10 + 7x + x2) ÷ (x + 2)
(x2 + 7x + 10) ÷ (x + 2)
Step 1 :
In the first step, we are going to divide the first term x2 of the dividend by the first term x of the divisor.
After changing the signs, +x2 and -x2 will get canceled. By simplifying, we get 5x + 10.
Step 2 :
In the second step again we are going to divide the first term that is 5x by the first term of divisor that is x.
Quotient = x + 5
Remainder = 0
Example 2 :
(3x3 + 11x2 + 9x - 5) ÷ (x + 2)
Solution :
Quotient = 3x2 + 5x - 1
Remainder = - 3
Example 3 :
(x2 - 25) ÷ (x + 5)
Solution :
The degree of the given polynomial is 2. But here we don't have x term, so we have to replace it by 0.
Quotient = x - 5
Remainder = 0
Example 4 :
(x2 - 1000) ÷ (x - 100)
Solution :
The degree of the given polynomial is 2. But here we don't have x term, so we have to replace it by 0.
Quotient = x + 100
Remainder = 0
Example 5 :
(30x3 + 50x) ÷ 5x
Solution :
Quotient = 6x2 + 10
Remainder = 0
Example 6 :
Find a and b if the polynomial x5 - ax + b is divisible by x2 - 4
Solution :
Quotient = x3 + 4x
Remainder = (-a + 16)x + b
Since it is given that x5 - ax + b is exactly divisible by x2 - 4, therefore remainder must be equal to zero.
That is,
(-a + 16)x + b = 0
By comparing coefficients,
(-a + 16)x + b = 0 . x + 0
- a + 16 = 0, b = 0
- a = - 16, b = 0
a = 16 and b = 0
So, a = 16 and b = 0
Example 7 :
The volume of a rectangular solid is given by the polynomial 3x4 - 3x3 - 33x2 + 54x. The length of the solid is given by 3x and the width is given by x - 2. Find the height of the solid.
Solution :
Given,
Volume of a rectangular solid = 3x4 - 3x3 - 33x2 + 54x
Length of the solid = 3x
Width of the solid = x - 2
Find the height of the solid.
Formula for Volume of a rectangle,
Volume of a rectangle = Length × Height × Width
3x4 - 3x3 - 33x2 + 54x = (3x) × Height × (x - 2)
3x4 - 3x3 - 33x2 + 54x = 3x2 - 6x × Height
Dividing by 3 on both sides,
x4 - x3 - 11x2 + 18x = x2 - 2x × Height
(x4 - x3 - 11x2 + 18x) ÷ x2 - 2x = Height
Quotient = x2 + x - 9
Remainder = 0
So, the height of the solid is x2 + x - 9
Example 8 :
The area of a rectangle is given by 3x3 + 14x2 - 23x + 6. The width of the rectangle is given by x + 6. Find an expression for the length of the rectangle.
Solution :
Given,
Area of a rectangle = 3x3 + 14x2 - 23x + 6
Width of the rectangle = x + 6
Find the length of the rectangle.
Formula for Area of a rectangle,
Area of a rectangle = Length × Width
3x3 + 14x2 - 23x + 6 = Length × x + 6
(3x3 + 14x2 - 23x + 6) ÷ x + 6 = Length
Quotient = 3x2 - 4x + 1
Remainder = 0
So, the length of the rectangle is 3x2 - 4x + 1
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