Procedure to find where the function is increasing or decreasing :
Example 1 :
Find the intervals in which
f(x) = 2x³+x²-20x
is increasing or decreasing
Solution :
f(x) = 2x3 + x2 - 20x
Step 1 :
f'(x) = 6x² + 2x - 20
÷ by 2 ⇒ 3x²+x-10
Step 2 :
f'(x) = 0
3x2+x-10 = 0
(3x - 5) (x + 2) = 0
3x-5 = 0 3x = 5 x = 5/3 |
x+2 = 0 x = -2 |
Step 3 :
We can split this into three intervals (-∞,-2) (-2,5/3) (5/3,∞).
Step 4 :
Now let us see the given function is increasing or decreasing in which intervals.
Interval -∞ < x < -2 -2 < x < 5/3 5/3 < x < ∞ |
3x-5 - + + |
x-2 - - + |
f'(x) + - + |
Step 5 :
The given is increasing on (-∞,-2] ∪ [5/3,-∞) and decreasing on [-2,5/3]
Example 2 :
Find the intervals in which
f(x) = x³ - 3 x + 1
is increasing or decreasing
Solution :
f(x) = x³ - 3 x + 1
f'(x) = 3x² - 3
÷ by 3 ⇒ x² - 1
f'(x) = 0
x² - 1 = 0
(x + 1) (x - 1) = 0
x+1 = 0 x = -1 |
x-1 = 0 x = 1 |
We can split this as three intervals (-∞,-1) (-1,1) (1,∞).
Now let us see the given function is increasing or decreasing in which intervals.
Interval -∞ < x < -1 -1 < x < 1 1 < x < ∞ |
x+1 - + + |
x-1 - - + |
f'(x) + - + |
The given is increasing on (-∞,-1] ∪ [1,∞) and decreasing on [-1, 1].
Example 3 :
Find the intervals in which f (x) = x - 2 sin x is increasing or decreasing
Solution :
f(x) = x - 2 sin x
f'(x) = 1 - 2 cos x
f'(x) = 0
1 - 2cos x = 0
-2 cos x = -1
cos x = 1/2
x = cos ⁻¹(1/2)
x = Π/3, 5Π/3
We can split this as three intervals (0,Π/3) (Π/3,5Π/3) (5Π/3,2Π).
Now let us see the given function is increasing or decreasing in which intervals.
Interval 0 < x < Π/3 Π/3 < x < 5Π/3 5Π/3 < x < 2Π |
1 - 2cos x - + - |
f'(x) - + + |
The given is increasing on [Π/3, 5Π/3] and decreasing on (0,Π/3] ∪ [5Π/3,2Π).
The following graphs show the derivative of 𝒇, 𝒇. Identify the intervals when 𝒇 is increasing and decreasing. Include a justification statement
Example 4 :.
Solution :
By observing the graph given above, (-∞, -1.5) and (-0.5, ∞) the curve is above the x-axis. Then it is increasing function in the interval mentioned.
By observing the graph above, (-1.5, -0.5) the curve is below the x-axis. Then it is decreasing function in the interval mentioned.
Example 5 :
Solution :
By observing the graph given above, (-1, 0) and (3, ∞) the curve is above the x-axis. Then it is increasing function in the interval mentioned.
By observing the graph above, (-∞, -1) and (0, 3) the curve is below the x-axis. Then it is decreasing function in the interval mentioned.
For each function, find the intervals where it is increasing and decreasing, and JUSTIFY your conclusion. Construct a sign chart to help you organize the information,
Example 6 :
f(x) = x3 - 12x + 1
Solution :
f(x) = x3 - 12x + 1
f'(x) = 3x2 - 12(1) + 0
= 3x2 - 12
f'(x) = 0
3x2 - 12 = 0
3(x2 - 4) = 0
3 (x + 2) (x - 2) = 0
x = -2 and x = 2
(-∞, -2) x = -3 ∈ (-∞, -2) |
f'(x) = 3 (x + 2) (x - 2) f'(-3) = 3(-3+2)(-3-2) = 3(-1)(-5) = 15 > 0 Increasing |
(-2, 2) x = 0 ∈ (-2, 2) |
f'(x) = 3 (x + 2) (x - 2) f'(0) = 3(0+2)(0-2) = 3(2)(-2) = -12 < 0 Decreasing |
(2, ∞) x = 3 ∈ (2, ∞) |
f'(x) = 3 (x + 2) (x - 2) f'(3) = 3(3+2)(3-2) = 3(5)(1) = 15 > 0 Increasing |
Increasing intervals are (-∞, -2) U (2, ∞) and decreasing interval is (-2, 2).
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