Length of arc = (θ/360) ⋅ 2πr
here θ - angle formed by two radius
r - radius
Example 1 :
Find the length of arc whose radius is 42 cm and central angle is 60°
Solution :
Length of arc = (θ/360) x 2πr
Here central angle (θ) = 60° and radius (r) = 42 cm
= (60°/360) ⋅ 2 ⋅ (22/7) ⋅ 42
= (1/6) ⋅ 2 ⋅ 22 ⋅ 6
= 2 ⋅ 22
= 44 cm
Example 2 :
Find the length of arc whose radius is 10.5 cm and central angle is 36°
Solution :
Length of arc = (θ/360) x 2πr
Here central angle (θ) = 36° and radius (r) = 10.5 cm
= (36°/360) ⋅ 2 ⋅ (22/7) ⋅ 10.5
= (1/10) ⋅ 2 ⋅ (22/7) ⋅ 10.5
= (1/5) ⋅ (22/7) ⋅ 10.5
= (22/7) ⋅ 2.1
= 22 ⋅ 0.3
= 6.6 cm
Example 3 :
Find the length of arc whose radius is 21 cm and central angle is 120°
Solution :
Length of arc = (θ/360) ⋅ 2πr
Here central angle (θ) = 120° and radius (r) = 21 cm
= (120°/360) ⋅ 2 ⋅ (22/7) ⋅ 21
= (1/3) ⋅ 2 ⋅ 22 ⋅ 3
= 2 ⋅ 22
= 44 cm
Example 4 :
Find the length of arc whose radius is 14 cm and central angle is 5°
Solution :
Length of arc = (θ/360) x 2πr
Here central angle (θ) = 5° and radius (r) = 14 cm
= (5°/360) ⋅ 2 ⋅ (22/7) ⋅ 14
= (1/72) ⋅ 2 ⋅ 22 ⋅ 2
= (1/36) ⋅ 2 ⋅ 22
= (1/18) ⋅ 22
= (1/9) ⋅ 11
= 11/9
= 1.22 cm
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