Question 1 :
Find a number b such that f ◦ g = g ◦ f , where
f(x) = 2x + b and g(x) = 3x + 4.
Solution :
L.H.S
f ◦ g (x) = f [g(x)]
= f(3x + 4)
= 2(3x + 4) + b
= 6x + 8 + b ------(1)
R.H.S :
g ◦ f (x) = g [f(x)]
= g(2x + b)
= 3(2x + b) + 4
= 6x + 3b + 4 ------(2)
(1) = (2)
6x + 8 + b = 6x + 3b + 4
b - 3b = 4 - 8
-2b = -4
b = 2
So, the value of b is 2.
Question 2 :
Find a number c such that f ◦ g = g ◦ f , where
f(x) = 5x − 2 and g(x) = cx − 3.
Solution :
L.H.S
f ◦ g (x) = f [g(x)]
= f(cx - 3)
= 5(cx - 3) - 2
= 5cx - 15 - 2
= 5cx - 17 ------(1)
R.H.S :
g ◦ f (x) = g [f(x)]
= g(5x - 2)
= c(5x - 2) - 3
= 5cx - 2c - 3 ------(2)
(1) = (2)
5cx - 17 = 5cx - 2c - 3
2c = -3 + 17
2c = 14
c = 14/2 = 7
c = 7
So, the value of c is 7.
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