Parabola symmetric about x-axis and open right ward :
Standard form of parabola
y2 = 4ax
Parabola symmetric about x-axis and open left ward :
Standard form of parabola
y2 = -4ax
Parabola symmetric about y-axis and open up ward :
Standard form of parabola
x2 = 4ay
Parabola symmetric about y-axis and open down ward :
Standard form of parabola
x2 = -4ay
Now let us see some examples based on the above concept.
Example 1 :
Find the focus, vertex, equation of directrix and length of the latus rectum of the parabola
x2 = 5y
Solution :
From the given equation, the parabola is symmetric about y - axis and it is open upward.
x2 = 5y
4a = 5
a = 5/4
Vertex : V (0, 0)
Focus : F (0, 5/4)
Equation of directrix : y = -5/4
Length of latus rectum : 4a = 4(5/4) ==> 5
Example 2 :
Find the focus, vertex, equation of directrix and length of the latus rectum of the parabola
x2 - 8y - 2x + 17 = 0
Solution :
x2 - 8y - 2x + 17 = 0
x2 - 2x = 8y - 17
x2 - 2x + 12 - 12 = 8y - 17
(x - 1)2 = 8y - 17 + 1
(x - 1)2 = 8y - 16
(x - 1)2 = 8(y - 2)
From the given equation, the parabola is symmetric about y - axis and it is open upward.
Let X = x - 1 and Y = y - 2
X2 = 8Y
4a = 8
a = 2
Referred to X and Y X = x - 1 and Y = y - 2 |
Referred to x and y x = X + 1 and y = Y + 2 |
Vertex (0, 0) Focus (0, 2) Equation of directrix Y = -a Y = -2 Length of latus rectum : 4a = 4(2) = 8 |
Vertex (1, 2) Focus (1, 4) Equation of directrix Y = 0 Length of latus rectum : 4a = 4(2) = 8 |
Example 3 :
Find the focus, vertex, equation of directrix and length of the latus rectum of the parabola
x2 = -16y
Solution :
From the given equation, the parabola is symmetric about y - axis and it is open downward.
x2 = -16y
4a = 16
a = 4
Vertex : V (0, 0)
Focus : F (0, -4)
Equation of directrix : y = a ==> y = 4
Length of latus rectum : 4a = 4(4) ==> 16
Example 4 :
Find the focus, vertex, equation of directrix and length of the latus rectum of the parabola
x2 + 4y - 6x + 17 = 0
Solution :
x2 + 4y - 6x + 17 = 0
x2 - 6x = -4y - 17
x2 - 6x + 32 - 32 = -4y - 17
(x - 3)2 = -4y - 17 + 9
(x - 3)2 = -4y - 8
(x - 3)2 = -4(y + 2)
From the given equation, the parabola is symmetric about y - axis and it is open downward.
Let X = x - 3 and Y = y + 2
X2 = -4Y
4a = 4
a = 1
Referred to X and Y X = x - 3 and Y = y + 2 |
Referred to x and y x = X + 3 and y = Y - 2 |
Vertex (0, 0) Focus (0, -1) Equation of directrix Y = a Y = 1 Length of latus rectum : 4a = 4(1) = 4 |
Vertex (3, -2) Focus (3, -3) Equation of directrix Y = -1 Length of latus rectum : = 4 |
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