Question 1 :
Find the values of other five trigonometric functions for the following:
sin θ = -2/3, θ lies in the IV quadrant.
Solution :
sin θ = Opposite side/hypotenuse side
sin θ = -2/3
Opposite side = 2, Hypotenuse side = 3
(Hypotenuse side)2 = (Opposite side)2 + (Adjacent side)2
Adjacent side = √(32 - 22)
= √(9 - 4)
= √5
Adjacent side = √5
Note : Since θ lies in 4th quadrant, all trigonometric ratios other than cos and sec will have negative sign.
cos θ = Adjacent side/hypotenuse side = √5/3
tan θ = Opposite side/Adjacent side = -2/√5
cosec θ = Hypotenuse side/Opposite side = -3/2
sec θ = Hypotenuse side/Adjacent side = 3/√5
cot θ = Adjacent side/Opposite side = -√5/2
Question 2 :
Find the values of other five trigonometric functions for the following:
tan θ = -2, θ lies in the II quadrant.
Solution :
tan θ = Opposite side/Adjacent side
tan θ = -2/1
Opposite side = 2, Adjacent side = 1
(Hypotenuse side)2 = (Opposite side)2 + (Adjacent side)2
Hypotenuse side = √(22 + 12)
= √(4 + 1)
= √5
Hypotenuse side = √5
Note : Since θ lies in 2nd quadrant, all trigonometric ratios other than sin and cosec will have negative sign.
sin θ = Opposite side/hypotenuse side = 2/√5
cos θ = Adjacent side/hypotenuse side = -1/√5
cosec θ = Hypotenuse side/Opposite side = √5/2
sec θ = Hypotenuse side/Adjacent side = -√5/1
cot θ = Adjacent side/Opposite side = -1/2
Question 3 :
Find the values of other five trigonometric functions for the following:
sec θ = 13/5, θ lies in the IV quadrant
Solution :
sec θ = Hypotenuse side/Hypotenuse side
sec θ = 13/5
Adjacent side = 5, Hypotenuse side = 13
(Hypotenuse side)2 = (Opposite side)2 + (Adjacent side)2
Opposite side = √(132 - 52)
= √(169 - 25)
= √144
Opposite side = 12
Note : Since θ lies in 4th quadrant, all trigonometric ratios other than tan and cot will have negative sign.
sin θ = Opposite side/hypotenuse side = -12/13
cos θ = Adjacent side/hypotenuse side = 5/13
tan θ = Opposite side/Adjacent side = 12/5
cosec θ = Hypotenuse side/Opposite side = 13/12
cot θ = Adjacent side/Opposite side = 5/12
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