Question 1 :
A gardener plans to plant 570 trees in 19 rows. Each row is to contain the same number of trees. How many trees will there be in each row ?
(A) 15 (B) 17 (C) 30
Solution :
Number of trees = 570
Number of rows = 19
Each row is containing same number of trees.
Number of trees in each row = 570/19
= 30
Hence 30 trees in each row.
Question 2 :
The population of a town is 450772. 1 out of every 14 persons is reported to be educated. In all, how many educated persons are there in the town.
(A) 32198 (B) 45123 (C) 15465
Solution :
Total population = 450772
Number of educated persons = 450772/14
= 32198
Hence the number of educated persons is 32198.
Question 3 :
The LCM of 20, 25, 30 and 40.
(A) 700 (B) 600 (C) 300
Solution :
Least common multiple = 5 x 2 x 2 x 5 x 3 x 2
= 600
Question 4 :
Given that LCM of two numbers is 16 and their product is 64, determine their HCF.
(A) 15 (B) 4 (C) 12
Solution :
Product of two numbers = L.C.M x H.C.F
l.C.M = 16, H.C.F = ?, product of two numbers = 64
64 = 16 x H.C.F
H.C.F = 64/16
H.C.F = 4
Question 5 :
The number of boys and girls in a school are 480 and 576 respectively. Express the ratio of the number of boys to that girls in the simplest form.
(A) 5:6 (B) 6:5 (C) 2:3
Solution :
Number of boys : Number of girls
= 480 : 576
= 480/576
= 5/6
= 5 : 6
Question 6 :
Find the third term of a proportion whose first, second and fourth terms are respectively 24, 8 and 5
(A) 20 (B) 18 (C) 15
Solution :
Let x be the third term.
24 : 8 :: x : 5
Product of extremes = Product of means
24 ⋅ 5 = 8 ⋅ x
x = (24 ⋅ 5)/8
x = 15
Question 7 :
Find 20% of 150
(A) 30 (B) 16 (C) 25
Solution :
20% of 150 = (20/100) ⋅ 150
= 30
Question 8 :
Find the value of 2y3 - 3y2 + y - 1, if y = -2
(A) -15 (B) -65 (C) -31
Solution :
p(y) = 2y3 - 3y2 + y - 1
p(-2) = 2(-2)3 - 3(-2)2 + (-2) - 1
= 2(-8) - 3(4) - 2 - 1
= -16 - 12 - 3
= -31
Hence the answer is -31.
Question 9 :
Sum of the three angles of a triangle is ________
(A) 150° (B) 180° (C) 120°
Solution :
The sum of the interior angles of a triangle is 180°.
Question 10 :
A tile is a square of side 25 cm. How many such tiles would be required to cover the floor of a square bath room of side is 3 m ?
(A) 13 (B) 17 (C) 12
Solution :
Number of square tiles = Area of bath room / Area of one square tile
Area of bath room = 3 m = 3 x 100 = 300 cm
Number of tiles = 300/25
= 12
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