GRADE 6 MATH WORKSHEET WITH ANSWERS

Question 1 :

A gardener plans to plant 570 trees in 19 rows. Each row is to contain the same number of trees. How many trees will there be in each row ?

(A) 15         (B) 17          (C) 30

Solution :

Number of trees  =  570

Number of rows  =  19

Each row is containing same number of trees.

Number of trees in each row  =  570/19

  =  30

Hence 30 trees in each row.

Question 2 :

The population of a town is 450772. 1 out of every 14 persons is reported to be educated. In all, how many educated persons are there in the town.

(A) 32198        (B) 45123            (C) 15465

Solution :

Total population  =  450772

Number of educated persons  =  450772/14

  =  32198

Hence the number of educated persons is 32198.

Question 3 :

The LCM of 20, 25, 30 and 40.

(A) 700        (B) 600          (C) 300

Solution :

Least common multiple  =  5 x 2 x 2 x 5 x 3 x 2 

  =  600

Question 4 :

Given that LCM of two numbers is 16 and their product is 64, determine their HCF.

(A) 15          (B) 4           (C) 12

Solution :

Product of two numbers  =  L.C.M x H.C.F

l.C.M  =  16, H.C.F  =  ?, product of two numbers  =  64

64  =  16 x H.C.F

H.C.F  =  64/16

H.C.F  =  4

Question 5 :

The number of boys and girls in a school are 480 and 576 respectively. Express the ratio of the number of boys to that girls in the simplest form.

(A) 5:6        (B) 6:5            (C) 2:3

Solution :

Number of boys : Number of girls

  =  480 : 576

  =  480/576

  =  5/6

  =  5 : 6

Question 6 :

Find the third term of a proportion whose first, second and fourth terms are respectively 24, 8 and 5

(A) 20       (B) 18        (C) 15

Solution :

Let x be the third term.

24 : 8 ::  x : 5

Product of extremes  =  Product of means

24 ⋅ 5  =  8 ⋅ x

x  =  (24 ⋅ 5)/8

x  =  15

Question 7 :

Find 20% of 150

(A) 30        (B) 16        (C) 25

Solution :

20% of 150  =  (20/100) ⋅ 150

  =  30

Question 8 :

Find the value of 2y- 3y2 + y - 1, if y = -2

(A) -15        (B) -65       (C) -31

Solution :

p(y)  =  2y- 3y2 + y - 1

p(-2)  =  2(-2)- 3(-2)2 + (-2) - 1

  =  2(-8) - 3(4) - 2 - 1

  =  -16 - 12 - 3

  =  -31

Hence the answer is -31.  

Question 9 :

Sum of the three angles of a triangle is ________

(A) 150°         (B) 180°           (C) 120°

Solution :

The sum of the interior angles of a triangle is 180°.

Question 10 :

A tile is a square of side 25 cm. How many such tiles would be required to cover the floor of a square bath room of side is 3 m ?

(A) 13         (B) 17         (C) 12

Solution :

Number of square tiles  =  Area of bath room / Area of one square tile

Area of bath room  =  3 m  =  3 x 100  =  300 cm

Number of tiles  =  300/25

  =  12

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