Question 1 :
Find the smallest number by which 3087 should be multiplied to obtain a perfect cube.
(A) 4 (B) 3 (C) 5
Solution :
By finding the prime factors of 3087, we know that
= ∛(3 ⋅ 3 ⋅ 7 ⋅ 7 ⋅ 7) So, 3 is the smallest number to be multiplied to obtain a perfect cube. |
Question 2 :
11025 students are sitting in a lawn in such a way that there are many students in a row as there are rows in lawn. Find the number of rows in the lawn.
(A) 205 (B) 105 (C) 115
Solution :
From the given information, we come to know that the number of rows in the lawn is equal to the number of students in a row.
Then we should find the square root of 11025.
So, the number of rows in the lawn is 105.
Question 3 :
Evaluate (243) -2/5
(A) 1/5 (B) 1/7 (C) 1/9
Solution :
(243) -2/5
243 = 3 ⋅ 3 ⋅ 3 ⋅ 3 ⋅ 3 = 35
(243) -2/5 = (35)-2/5
= 3-2
= 1/32 = 1/9
Question 4 :
Evaluate (52 + 122)1/2
(A) 17 (B) 15 (C) 13
Solution :
(52 + 122)1/2 = (52 + 122)1/2
= (25 + 144)1/2
= √169
= √(13 ⋅ 13)
= 13
Question 5 :
If a + b + c = 9 and ab + bc + ca = 23, find the value of a2 + b2 + c2
(A) 35 (B) 45 (C) 55
Solution :
(a + b + c)2 = a2 + b2 + b2 + 2ab + 2bc + 2ca
(a + b + c)2 = a2 + b2 + b2 + 2(ab + bc + ca)
92 = a2 + b2 + b2 + 2(23)
81 = a2 + b2 + b2 + 46
81 - 46 = a2 + b2 + b2
a2 + b2 + b2 = 35
Question 6 :
What is the degree of the polynomial 4 + 3x - 7x3 + 5x4
(A) 4 (B) 3 (C) 1
Solution :
The highest power of the polynomial is know as degree.
So, the degree of the polynomial is 4.
Question 7 :
Solve the following 3x / (2x - 5) = 12/5
(A) 20/3 (B) 10/7 (C) 15/8
Solution :
3x / (2x - 5) = 12/5
5(3x) = 12 (2x - 5)
15x = 24 x - 60
15x - 24x = -60
-9x = -60
x = 60/9
x = 20/3
So, the required fraction is 20/3.
Question 8 :
The numerator of a rational number is less than its denominator by the number 3. If the numerator becomes three times and the denominator is increased by 20, the new fraction became 1/8. Find the required fraction.
(A) 1/3 (B) 1/2 (C) 1/4
Solution :
Let x = denominator
x-3 = numerator
3 (x-3) / (x+20) = 1/8
(3x-9) / (x+20) = 1/8
8(3x-9) = (x+20)
24x - 72 = x + 20
Subtract both sides by x
24x - x - 72 = 20
Add both sides by 72
23x = 20 + 72
x = 92/23 = 4 (denominator)
Numerator = 4 - 3 = 1
Hence the required fraction is 1/4.
Question 9 :
In a circle with center O and the radius 13 cm, AB is a chord of length 24 cm. Find the distance between the chord and the center.
(A) 6 cm (B) 8 cm (C) 5 cm
Solution :
In triangle OCB,
OB2 = OC2 + CB2
OC bisects the chord.
132 = OC2 + 122
OC2 = 169 - 144
OC2 = 25
OC = 5 cm
So, the distance between center and the chord is 5 cm.
Question 10 :
Find the value of x° if the lines AB and CD are parallel to each other
(A) 0° (B) 180° (C) 225°
Solution :
x = 360 - (45 + 30)
x = 360 - 75
x = 285
So, the required angle is 285.
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