Let us consider the first 'n' natural numbers.
1, 2, 3, ........... n
If you want to find the number of numbers which are divisible by 6 in the first natural numbers, you have to divide 'n' by 6.
Let n/6 = k.
If 'k' is an integer, then the number of numbers which are divisible by 6 in the first 'n' natural numbers is 'k'.
If 'k' is a decimal number, then the number of numbers which are divisible by 6 in the first 'n' natural numbers is the largest integer contained in 'k'.
Consider the following example to understand the above concept.
Find the number of numbers which are divisible by 6 in the first 100 natural numbers.
Divide 100 by 6.
100 ÷ 6 ≈ 16.67
The quotient of (100 ÷ 6) is about 16.67 which is a decimal number. Don't round 16.67 to the next integer 17.
The largest integer contained in 16.67 is 16.
Therefore, the number of numbers which are divisible by 6 in the first 100 natural numbers is 16.
6, 12, 18, 24, 30, 36, 42, 48,
54, 60, 66, 72, 78, 84, 90, 96
Question :
How many 3 digit numbers are divisible by 6 in all ?
Answer :
The smallest three digit number is 100 and the largest three digit number is 999.
We have to find the number of numbers which are divisible by 6 from 100 to 999.
Number of numbers divisible by 6 from 1 to 999 :
999 ÷ 6 = 166.5
The largest integer contained in 166.5 is 166.
Number of numbers divisible by 6 from 1 to 99 :
99 ÷ 6 = 16.5
The largest integer contained in 16.5 is 16.
Number of numbers divisible by 6 from 100 to 999 :
= 166 - 16
= 150
Therefore, number of 3 digit numbers which are divisible by 6 is 150.
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