Length of the tangent = √ (x₁²
+ y₁² + 2gx₁ +2fy₁ + c)
To check if the given point lie on the circle, inside the circle or out side the circle, we use the formula for length of tangent.
(i) If the length is 0.Then we can say, the given point must lie on the circle.
√ (x₁² + y₁² + 2gx₁ +2fy₁ + c) = 0
(ii) If the length is > 0 .Then we can say, the point must lie outside the circle.
√ (x₁² + y₁² + 2gx₁ +2fy₁ + c) > 0
(iii) If the length is < 0 .Then we can say, the point must lie inside the circle.
√ (x₁² + y₁² + 2gx₁ +2fy₁ + c) < 0
Example 1 :
Show that the point (2, 3) lies inside the circle x2 + y2 − 6x − 8y + 12 = 0.
Solution :
The length of the tangent PT from P(x1, y1) to the circle
x2 + y2 + 2gx +2fy + c = 0 is
PT = x12 + y12 + 2gx1 + 2fy1 + c
PT = √(22 + 32 − 6.2 − 8.3 + 12)
= √(4 + 9 − 12 − 24 + 12)
= − 11 < 0
The point (2, 3) lies inside the circle
Example 2 :
Show that the point (2,-1) lies outside the circle x²+y²- 6x - 8y + 12 = 0
Solution :
Length of the tangent
= √ (x₁² + y₁² + 2gx₁ +2fy₁ + c)
Here x₁ = 2 and y₁ = -1
= √ (2)² + (-1)² - 6(2) - 8 (-1) + 12
= √ 4 + 1 - 16 + 8 + 12
= √5 + 8 + 12 + 1 - 8
= √ 26 - 8
= √18 = 3√2 units
The length of tangent is positive. So the given point lies outside the circle.
Example 3 :
Is the point (7, − 11) lie inside or outside the circle x2 + y2 − 10x = 0 ?
Solution :
To know that where does the given point lie in the circle, we have to find the length of tangent.
Length of the tangent
= √ (x₁² + y₁² + 2gx₁ +2fy₁ + c)
Here x₁ = 7 and y₁ = -11
= √ x2 + y2 − 10x
= √72 + (-11)2 − 10(7)
= √49 + 121 - 70
= √ 170 - 70
= √100 = 10 > 0
Hence the given point (7, -11) outside the circle.
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