Evaluate the following if z = 5 - 2i and w = -1 + 3i.
Example 1 :
z + w
Solution :
z + w = (5 - 2i) + (-1+ 3i)
= (5 - 1) + (-2i + 3i)
= 4 + i
Example 2 :
z − iw
Solution :
z - iw = (5 − 2i) - i(-1+ 3i)
= 5 − 2i + i - 3i2
= 5 − 2i + i - 3(-1)
= 5 − 2i + i + 3
= (5 + 3) + i(-2 + 1)
= 8 - i
Example 3 :
2z + 3w
Solution :
2z + 3w = 2(5 − 2i) + 3(-1+ 3i)
= 10 - 4i - 3 + 9i
= (10 - 3) + i(9 - 4)
= 7 + 5i
Example 4 :
zw
Solution :
zw = (5 − 2i) (-1+ 3i)
= -5 + 15i + 2i - 6i2
= -5 + 15i + 2i - 6(-1)
= (-5 + 6) + i(15 + 2)
= 1 + 17i
Example 5 :
z2 + 2zw+ w2
Solution :
z = (5 − 2i) z2 = (5 − 2i)2 = 52 + (2i)2 - 2(5) (2i) = 25 + 4i2 - 20i = 25 + 4(-1) - 20i = 25 - 4 - 20i = 21 - 20i |
w = (-1 + 3i) w2 = (-1 + 3i)2 = (-1)2 + (3i)2 - 2(-1) (3i) = 1 + 9i2 + 6i = 1 + 9(-1) - 6i = 1 + 9 - 6i = 10 - 6i |
z2 + 2zw+ w2 = 21 - 20i + 2 + 2( 1 + 17i) + 10 - 6i
= 21 - 20i + 2 + 34i + 10 - 6i
= (21 + 2 + 10) + i(-20 + 34 - 6)
= 33 + 8i
Example 6 :
(z + w)2
(z + w)2 = (4 + i)2
= 42 + i2 + 2(4)i
= 16 - 1 + 8i
= 15 + 8i
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