Complex roots of an equation will occur in conjugate pair. That is, if (a + ib) is a root, then (a - ib) is the other root of the same equation.
Example 1 :
Solve the following equation, if (2 + i√3) is a root.
x4 - 4x2 + 8x + 35 = 0
Solution :
Since (2 + i√3) is a complex root, (2 - i√3) must be the other root.
x = 2 + i√3 or x - (2 + i√3) = 0
x = 2 - i√3 or x - (2 - i√3) = 0
Quadratic polynomial with the roots (2 + i√3) and (2 - i√3) :
= x2 - (sum of the roots)x + product of the roots
= x2 - [(2 + i√3) + (1 - i2√3)]x + (2 + i√3)(2 - i√3)
= x2 - [2 + i√3 + 2 - i√3]x + 22 - (√3i)2
= x2 - 4x + 4 - (√3)2i2
= x2 - 4x + 4 - 3(-1)
= x2 - 4x + 4 + 3
= x2 - 4x + 7
(x2 - 4x + 7) is a factor of (x4 - 4x2 + 8x + 35).
Let (x2 + ax + b) be the other factor.
Then,
(x2 + ax + b)(x2 - 4x + 7) = x4 - 4x2 + 8x + 35
Comparing the constant terms,
7b = 35
b = 5
Comparing the coefficient of x terms,
7a - 4b = 8
Substitute b = 5.
7a - 4(5) = 8
7a - 20 = 8
7a = 28
a = 4
x2 + ax + b ----> x2 + 4x + 5
Solving the equation x2 + 4x + 5 = 0, we get
x = -2 + i or -2 - i
Therefore, the roots of the given equation are
2 + i√3, 2 - i√3, -2 + i and -2 - i
Example 2 :
Solve the following equation, if (3 + i) is a root.
x4 - 8x3 + 24x2 - 32x + 20 = 0
Solution :
Since (3 + i) is a complex root, (3 - i) must be the other root.
x = 3 + i or x - (3 + i) = 0
x = 3 - i or x - (3 - i) = 0
Quadratic polynomial with the roots (3 + i) and (3 - i) :
= x2 - (sum of the roots)x + product of the roots
= x2 - [(3 + i) + (3 - i)]x + (3 + i)(3 - i)
= x2 - [3 + i + 3 - i]x + 32 - i2
= x2 - 6x + 9 - (-1)
= x2 - 6x + 9 + 1
= x2 - 6x + 10
(x2 - 6x + 10) is a factor of (x4 - 8x3 + 24x2 - 32x + 20).
Let (x2 + ax + b) be the other factor.
Then,
(x2 + ax + b)(x2 - 6x + 10) = x4 - 8x3 + 24x2 - 32x + 20
Comparing the constant terms,
10b = 20
b = 2
Comparing the coefficient of x terms,
10a - 6b = -32
Substitute b = 2.
10a - 6(2) = -32
10a - 12 = -32
10a = -20
a = -2
x2 + ax + b ----> x2 - 2x + 2
Solving the equation x2 - 2x + 2 = 0, we get
x = 1 + i or 1 - i
Therefore, the roots of the given equation are
3 + i, 3 - i, 1 + i and 1 - i
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