Consider the graph of a parabola shown below.
The parabola opens to the right with vertex (0, 0).
The equation of the parabola shown above in standard form :
y2 = 4ax
Latus rectum LL' passes through the focus (a, 0).
Hence the point L is (a, y1).
There fore,
y12 = 4a(a)
y12 = 4a2
Take square root on both sides.
y1 = ±√(4a2)
y1 = ±2a
y1 = 2a or -2a
The end points of latus rectum are (a, 2a) and (a,-2a).
Therefore length of the latus rectum LL' = 4a.
y2 = 4ax ----> opens to the right
y2 = -4ax ----> opens to the left
x2 = 4ay ----> opens up
x2 = -4ay ----> opens down
(y - k)2 = 4a(x - h) ----> opens to the right
(y - k)2 = -4a(x - h) ----> opens to the left
(x - h)2 = 4a(y - k) ----> opens up
(x - h)2 = -4a(y - k) ----> opens down
Find the length of latus rectum of the following parabolas :
Example 1 :
x2 = -4y
Solution :
The given equation equation of the parabola in standard form.
Comparing x2 = -4y and x2 = -4ay,
4a = 4
So, the length of latus rectum is 4 units.
Example 2 :
y2 - 8x + 6y + 9 = 0
Solution :
The given equation of the parabola is not in standard form.
Write the equation of the parabola in standard form.
y2 - 8x + 6y + 9 = 0
y2 + 6y = 8x - 93
y2 + 2(y)(3) = 8x - 9
y2 + 2(y)(3) + 32 - 32 = 8x - 9
(y + 3)2 - 32 = 8x - 9
(y + 3)2 - 9 = 8x - 9
(y + 3)2 = 8x
(y + 3)2 = 8(x - 0)
Now, the equation of the parabola is in standard form.
Comparing (y - k)2 = 4a(x - h) and (y + 3)2 = 8(x - 0),
4a = 8
So, the length of latus rectum is 8 units.
Example 3 :
x2 - 2x + 16y + 17 = 0
Solution :
The given equation of the parabola is not in standard form.
Write the equation of the parabola in standard form.
x2 - 2x = -16y - 17
x2 - 2(x)(1) = -16y - 17
x2 - 2(x)(1) + 12 - 12 = -16y - 17
(x - 1)2 - 12 = -16y - 17
(x - 1)2 - 1 = -16y - 17
(x - 1)2 = -16y - 16
(x - 1)2 = -16(y + 1)
Now, the equation of the parabola is in standard form.
Comparing (x - h)2 = -4a(y - k) and (x - 1)2 = -16(y + 1),
4a = 16
So, the length of latus rectum is 16 units.
Example 4 :
y = 2x2+ 3x + 4
Solution :
The given equation of the parabola is not in standard form.
Write the equation of the parabola in standard form.
y = 2x2+ 3x + 4
or
2x2+ 3x = y - 4
4a = 1/2 or 0.5
So, the length of latus rectum is 0.5 units.
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