There are two types of sequence,
Finite Sequence :
If the number of elements in a sequence is finite then it is called a Finite sequence.
Infinite Sequence :
If the number of elements in a sequence is infinite then it is called an Infinite sequence.
Question 1 :
Find the next three terms of the following sequence.
(i) 8, 24, 72, …
Solution :
To find the next three, first we have to find out the pattern followed in sequence.
Pattern :
Multiplying the first term by 3, we get the second term.Multiplying the second term by 3, we get the third term.
4th term = 3 (72) = 216
5th term = 216 (3) = 648
6th term = 648(3) = 1944
Hence the next three terms are 216, 648, 1944.
(ii) 5, 1,-3,…
Solution :
Pattern :
By subtracting 4 from the 1st term, we get second term. By subtracting 4 from 2nd term, we get 3rd term.
4th term = -3 - 4 = -7
5th term = -7 - 4 = -11
6th term = -11 - 4 = -15
Hence the next three terms are -7, -11, -15.
(iii) 1/4, 2/9, 3/16,…
Solution :
Pattern :
General term = n [1/(n + 1)]2
n is elements of natural numbers.
4th term = 4 [1/(4 + 1)]2
= 4[1/5]2
= 4/25
5th term = 5 [1/(5 + 1)]2
= 5[1/6]2
= 5/36
6th term = 6 [1/(6 + 1)]2
= 6[1/7]2
= 6/49
Hence the next three terms are 4/25, 5/36, 6/49.
Question 2 :
Find the first four terms of the sequences whose nth terms are given by
(i) an = n3 −2
Solution :
To find the 1st term, we have to apply n = 1
an = n3 −2 n = 1 a1 = 13 −2 = 1 - 2 a1 = -1 |
an = n3 −2 n = 2 a2 = 23 −2 = 8 - 2 a2 = 6 |
an = n3 −2 n = 3 a3 = 33 −2 = 27 - 2 a3 = 25 |
an = n3 −2 n = 4 a4 = 43 −2 = 64 - 2 a4 = 62 |
Hence the first four terms are -1, 6, 25, 62.
(ii) an = (−1)n+1 n(n + 1)
Solution :
an = (−1)n+1 n(n + 1) n = 1 = (−1)n+1 n(n + 1) = (−1)1+1 1(1 + 1) = 1 (2) a1 = 2 |
n = 2 = (−1)n+1 n(n + 1) = (−1)2+1 2(2 + 1) = -1 (6) a2 = -6 |
n = 3 = (−1)n+1 n(n + 1) = (−1)3+1 3(3 + 1) = 1 (12) a3 = 12 |
n = 4 = (−1)n+1 n(n + 1) = (−1)4+1 4(4 + 1) = -1 (20) a4 = -20 |
Hence the first four terms are 2, -6, 12, -20.
(iii) an = 2n2 - 6
Solution :
an = 2n2 - 6 n = 1 = 2(1)2 - 6 a1 = -4 |
an = 2n2 - 6 n = 2 = 2(2)2 - 6 a2 = 2 |
an = 2n2 - 6 n = 3 = 2(3)2 - 6 a3 = 12 |
an = 2n2 - 6 n = 4 = 2(4)2 - 6 a4 = 26 |
Hence the four terms are -4, 2, 12, 26.
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