In this section, we are going you to see how to graph a circle on the xy-plane when its equation is given. To graph a circle on the xy-plane, we need to know its center and radius. So, we have to find the center and radius from the equation of the circle given.
Equation of a circle in standard form with center (0, 0) :
x2 + y2 = r2
Equation of a circle in standard form with center (h, k) :
(x - h)2 + (y - k)2 = r2
Equation of a circle in general form :
x2 + y2 + 2gx + 2fy + c = 0
center = (-g, -f)
radius = √(g2 + f2 - c)
Graph the circles whose equations are given :
Example 1 :
x2 + y2 = 16
Solution :
The the given equation is in the form of
x2 + y2 = r2.
Center of the circle is (0, 0).
r2 = 16
r = √16
radius = 4 units
Example 2 :
(x - 2)2 + (y + 3)2 = 16
Solution :
The the given equation of the circle is in the form of
(x - h)2 + (y - k)2 = r2 ----(1)
Center of the circle is (h, k) and radius is r.
(x - 2)2 + (y + 3)2 = 16
(x - 2)2 + (y - (-3))2 = 42 ----(2)
Comparing (1) and (2),
center (h, k) = (2, -3)
r2 = 42
r = 4
radius = 4 units
Example 3 :
x2 + y2 - 2x - 6y + 1 = 0
Solution :
The equation of the given circle is in general form
x2 + y2+ 2gx + 2fy + c = 0 ----(1)
center = (-g, -f)
radius = √(g2 + f2 - c)
x2 + y2 - 2x - 6y + 1 = 0 ----(2)
Comparing (1) and (2),
2g = -2 ----> g = -1 ----> -g = 1
2f = -6 ----> f = -3 ----> -f = 3
center (-g, -f) = (1, 3)
radius = √(g2 + f2 - c)
= √(12 + 32 - 1)
= √(1 + 9 - 1)
= √9
r = 3 units
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