Quantity 1 :
Increase 30 in the ratio 2 : 3.
Quantity 2 :
Decrease 75 in the ratio 5 : 4.
Quantity 3 :
James weighs 140 lb.56.7 kilograms. If he reduces his weight in the ratio 7 : 6, find his new weight.
Quantity 4 :
John has to travel from the city A to city B. The distance from city A to city B through the city C is 420 miles. If John travels from the city A to city B through the city D, the distance is decreased in the ratio 7 ; 5. Find the distance from the city A to city B through the city D.
Quantity 5 :
Edward weighed 140 lb. and reduced his weight to 112 lb. In what ratio did Edward reduce his weight? 4.
1. Answer :
Original quantity = 30.
Original quantity 30 increased in the ratio 2 : 3.
New Quantity :
= (3 x 30)/2
= 90/2
= 45
2. Answer :
Original quantity = 75.
Original quantity 75 decreased in the ratio 5 : 4.
New Quantity :
= (4 x 75)/5
= 300/5
= 60
3. Answer :
Original weight of James = 56.7 kilograms.
He reduces his weight in the ratio 7 : 6.
His new weight :
= (6 x 56.7)/7
= 48.6 kilograms
4. Answer :
Distance from A to B through C = 420 miles.
The distance 420 miles is decreased in the ratio He reduces his weight in the ratio 7 : 6.
Distance from A to B through D :
= (6 x 420)/7
= 2520/7
= 360 miles
5. Answer :
Original weight of Edward = 140 lb.
New weight of Edward = 112 lb.
Let the weight be reduced in the ratio a : b.
Then,
112 = (b ⋅ 140)/a
Multiply both sides by a.
112 ⋅ a = 140 ⋅ b
Divide both sides by 112b.
a/b = 140/112
a/b = 5/4
a : b = 5 : 4
Therefore, Edward reduced his weight in the ratio 5 : 4.
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