INVERSE FUNCTIONS USING TABLES

Example 1 :

Suppose f is the function whose domain is the four numbers {√2, 8, 17, 18}, with the values of f given in the table shown here in the margin.

(a) What is the range of f ?

(b) Explain why f is a one-to-one function.

(c) What is the table for the function f −1?

Solution :

(a) In the table above, x represents domain and f(x) represents range. Hence the range of the function is

{3, -5, 6, 1}

(b) From the table above, it is clear that every element of x is associated with an unique element of f(x). Hence it is one to one function.

(c)  From the table above, 

f(√2) = 3, f(8) = -5, f(17) = 6, f(18) = 1

f-1(3) = √2, f-1(-5) = 8, f-1(6) = 17, f-1(1) = 18

The table for the function f-1 :

Example 2 :

For f and g are functions, each of whose domain consists of four numbers, with f and g defined by the tables below:

(a) What is the domain of f ?

(b) What is the range of f ?

(c) Sketch the graph of f.

(d) Give the table of values for f−1.

(e) What is the domain of f−1?

(f) What is the range of f−1?

(g) Sketch the graph of f-1.

(h) Give the table of values for f−1 o f.

(i) Give the table of values for f o f-1.

Solution :

(a) Domain of f = {1, 2, 3, 4}

(b) Range of f = {2, 3, 4, 5}

(c) The graph of f consists of all points of the form

(x, f(x))

as x varies over the domain of f . Thus the graph of f, shown below, consists of the four points :

(1, 4), (2, 5), (3, 2), (4, 3)

(d) The table for the inverse of a function is obtained by interchanging the two columns of the table for the function (after which one can, if desired, reorder the rows, as has been done below) :

(e) Domain of f-1 = {2, 3, 4, 5}

(f) Range of f-1 = {1, 2, 3, 4}

(g) The graph of f-1 consists of all points of the form

(x, f-1(x))

as x varies over the domain of f-1. Thus the graph of f-1, shown below, consists of the four points :

(4, 1), (5, 2), (2, 3), (3, 4)

(h)Table of values for f-1 o f :

(f −1o f) (1) = f−1[f(1)] = f−1(4) = 1

(f −1o f) (2) = f−1[f(2)] = f−1(5) = 2

(f −1o f) (3) = f−1[f(3)] = f−1(2) = 3

(f −1o f) (4) = f−1[f(4)] = f−1(3) = 4

(i) Table of values for f o f-1 :

(f o f −1) (2) = f[(f−1(2)] = f(3) = 2

(f o f −1) (3) = f[f−1(3)] = f(4) = 3

(f o f−1) (4) = f[f −1(4)] = f(1) = 4

(f o f −1) (5) = f[f−1(5)] = f(2) = 5

Example 3 :

The following table gives values of a function f(x) for six inputs 0, 1, 2, 3, 4, and 5.

inverse-function-using-table-q1

Read the table to find:

a. f(4) = 

b. f(2) =

c. f(0) = 

d. f(5) =

e. f –1 (10) =

f. f–1(3) =

g. f –1(0) = 

h. f –1(12) =

Solution :

a. f(4) = 0

b. f(2) = 3

c. f(0) = 12

d. f(5) = 8

e. f –1 (10) = 3

f. f–1(3) = 2

g. f –1(0) = 4 

h. f –1(12) = 0

Example 4 :

If f(x) = (1/8)x - 3, g(x) = x3, h(x) = 2x + 1

Find (f∘g)-1 (5) ?

Solution :

To evaluate (f∘g)-1 (x), first let us find (f∘g) (x) and then find its inverse.

(f∘g) (x) = f[g(x)]

= f[x3]

f[g(x)] = (1/8)x3 - 3

Finding inverse of (f∘g) (x) :

Let y = (1/8)x3 - 3

y + 3 = (1/8)x3

x3 = 8(y + 3)

x3 = 8y + 24

x = (8y + 24)1/3

(f∘g)-1 (x) = (8x + 24)1/3

(f∘g)-1 (5) = (8(5) + 24)1/3

= (40 + 24)1/3

= (64)1/3

= 4

Example 5 :

Find a table of values for each function and its inverse. 

f(x) = 3x + 1

inverse-of-function-from-table-q1

Solution :

f(x) = 3x + 1

When x = -4

f(-4) = 3(-4) + 1

f(-4) = -11

When x = -3

f(-3) = 3(-3) + 1

f(-3) = -8

When x = -2

f(-2) = 3(-2) + 1

f(-2) = -5

When x = -1

f(-1) = 3(-1) + 1

f(-1) = -2

When x = 0

f(0) = 3(0) + 1

f(0) = 1

When x = 1

f(1) = 3(1) + 1

f(1) = 4

When x = 2

f(2) = 3(2) + 1

f(2) = 7

Writing these values as ordered pairs for the function f(x) :

(-4, -11) (-3, -8) (-2, -5) (-1, -2) (0, 1) (1, 4) and (2, 7)

Ordered pairs for the function f-1(x) :

(-11, -4) (-8, -3) (-5, -2) (-2, -1) (1, 0) (4, 1) and (7, 2)

Example 6 :

Let n = f(t) = 0.25 t – 1.67 represent the number of people (in millions) undergoing laser eye surgery in the year that is t years since 1990.

a) Find & interpret f(10).

b)  Find an equation for f –1.

c) Find & interpret f –1(3).

d) What is the slope of f –1?

What does it mean in the context of this problem ?

Solution :

a) f(t) = 0.25 t – 1.67

f(10) = 0.25 (10) – 1.67

= 2.5 - 1.67

= 0.83

In the year 2000, 83 million people were  undergoing laser eye surgery

b) Finding inverse :

f(t) = 0.25 t – 1.67

Let y = 0.25 t – 1.67

y + 1.67 = 0.25t

(y + 1.67)/0.25 = t

f –1(x) = (x + 1.67)/0.25

Find an equation for f –1.

c)  f –1(3) =  (3 + 1.67)/0.25

= 4.67/0.25

= 18.68

Approximately 19 years

After 19 years in the year of 2009 3 million people were undergoing the laser eye surgery.

d) slope of f –1 is 4.

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