In each case, find the least common multiple of the numbers by prime factorization.
Problem 1 :
4 and 6
Problem 2 :
2 and 3
Problem 3 :
4 and 5.
Problem 4 :
3 and 6
Problem 5 :
12 and 18
Problem 6 :
24 and 60
Problem 7 :
4, 5 and 8
Problem 8 :
48, 72 and 108
Problem 9 :
4, 6, 8 and 12
Problem 10 :
2, 3, 4 and 5
Problem 11 :
2, 4, 5 and 8
Problem 12 :
3, 6, 7 and 14
1. Answer :
4 and 6
Resolve the given numbers into their prime factors.
From the above division,
4 = 2 x 2
6 = 2 x 3
The different prime factors are 2 and 3.
The prime factor 2 appears a maximum of 2 times in the prime factorization of 4.
The prime factor 3 appears a maximum of 1 time in the prime factorization of 6.
Therefore, the least common multiple of 4 and 6 is
= 2 x 2 x 3
= 12
2. Answer :
2 and 3
There is no common divisor for 2 and 3 other than 1. So, 2 and 3 are relatively prime.
To get least common multiple of relatively prime numbers, we have to multiply them.
Therefore, the least common multiple of 2 and 3 is
= 2 x 3
= 6
3. Answer :
4 and 5
There is no common divisor for 4 and 5 other than 1. So, 4 and 5 are relatively prime.
To get least common multiple of relatively prime numbers, we have to multiply them.
Therefore, the least common multiple of 4 and 5 is
= 4 x 5
= 20
4. Answer :
3 and 6
Since 3 is a prime number, we don't have to resolve it into prime factors anymore.
Resolve 6 into its prime factors.
From the above division,
6 = 2 x 3
3 is already a prime number.
3 = 3
The different prime factors are 2 and 3.
The prime factor 2 appears a maximum of 1 time in the prime factorization of 6.
The prime factor 3 appears a maximum of 1 time in the prime factorization of 6 and 3.
Therefore, the least common multiple of 3 and 6 is
= 2 x 3
= 6
5. Answer :
12 and 18
Resolve 12 and 18 into their prime factors.
From the above division,
12 = 2 x 2 x 3
18 = 2 x 3 x 3
The different prime factors are 2 and 3.
The prime factor 2 appears a maximum of 2 times in the prime factorization of 12.
The prime factor 3 appears a maximum of 2 times in the prime factorization of 18.
Therefore, the least common multiple of 12 and 18 is
= 2 x 2 x 3 x 3
= 36
6. Answer :
24 and 60
Resolve 24 and 60 into their prime factors.
From the above division,
24 = 2 x 2 x 2 x 3
60 = 2 x 2 x 3 x 5
The different prime factors are 2, 3 and 5.
The prime factor 2 appears a maximum of 3 times in the prime factorization of 24.
The prime factor 3 appears a maximum of 1 time in the prime factorization of 24 and 60.
The prime factor 5 appears a maximum of 1 time in the prime factorization of 60.
Therefore, the least common multiple of 24 and 60 is
= 2 x 2 x 2 x 3 x 5
= 120
7. Answer :
4, 5 and 8
Since 5 is a prime number, we don't have to resolve it into prime factors anymore.
Resolve 4 and 8 into their prime factors.
From the above division,
4 = 2 x 2
8 = 2 x 2 x 2
5 is already a prime number.
5 = 5
The different prime factors are 2 and 5.
The prime factor 2 appears a maximum of 3 times in the prime factorization of 8.
The prime factor 5 appears a maximum of 1 time in the prime factorization of 5.
Therefore, the least common multiple of 4, 5 and 8 is
= 2 x 2 x 2 x 5
= 40
8. Answer :
48, 72 and 108
Resolve 48, 72 and 108 into their prime factors.
From the above division,
48 = 2 x 2 x 2 x 2 x 3
72 = 2 x 2 x 2 x 3 x 3
108 = 2 x 2 x 3 x 3 x 3
The different prime factors are 2 and 3.
The prime factor 2 appears a maximum of 4 times in the prime factorization of 48.
The prime factor 3 appears a maximum of 3 times in the prime factorization of 108.
Therefore, the least common multiple of 48, 72 and 108
= 2 x 2 x 2 x 2 x 3 x 3 x 3
= 432
9. Answer :
4, 6, 8 and 12
Resolve 4, 6, 8 and 12 into their prime factors.
From the above division,
4 = 2 x 2
6 = 2 x 3
8 = 2 x 2 x 2
12 = 2 x 2 x 3
The different prime factors are 2 and 3.
The prime factor 2 appears a maximum of 3 times in the prime factorization of 8.
The prime factor 3 appears a maximum of 1 time in the prime factorization of 6 and 12.
Therefore, the least common multiple of 4, 6, 8 and 12 is
= 2 x 2 x 2 x 3
= 24
10. Answer :
2, 3, 4 and 5
There is no common divisor for all the four numbers 2, 3, 4 and 5. So, the given numbers are relatively prime.
To get least common multiple of relatively prime numbers, we have to multiply them.
Therefore, the least common multiple of 2, 3, 4 and 5 is
= 2 x 3 x 4 x 5
= 120
11. Answer :
2, 4, 5 and 8
Since 2 and 5 are prime numbers, we don't have to resolve them into prime factors anymore.
Resolve 4 and 8 into their prime factors.
From the above division,
4 = 2 x 2
8 = 2 x 2 x 2
2 and 5 are already prime numbers.
2 = 2
5 = 5
The different prime factors are 2 and 5.
The prime factor 2 appears a maximum of 3 times in the prime factorization of 8.
The prime factor 5 appears a maximum of 1 time in the prime factorization of 5.
Therefore, the least common multiple of 2, 4, 5 and 8 is
= 2 x 2 x 2 x 5
= 40
12. Answer :
3, 6, 7 and 14
Since 3 and 7 are prime numbers, we don't have to resolve them into prime factors anymore.
Resolve 6 and 14 into their prime factors.
From the above division,
6 = 2 x 3
14 = 2 x 7
3 and 7 are already prime numbers.
3 = 3
7 = 7
The different prime factors are 2, 3 and 7.
The prime factor 2 appears a maximum of 1 time in the prime factorization of 6 and 14.
The prime factor 3 appears a maximum of 1 time in the prime factorization of 6 and 3.
The prime factor 7 appears a maximum of 1 time in the prime factorization of 14 and 7.
Therefore, the least common multiple of 3, 6, 7 and 14 is
= 2 x 3 x 7
= 42
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