Question 1 :
Let b > 0 and b ≠ 1. Express y = bx in logarithmic form. Also state the domain and range of the logarithmic function.
Solution :
y = bx
logby = x
Domain : (0, ∞)
Range : (-∞, ∞)
Question 2 :
Compute :
log927 − log279
Solution :
= log927 - log279
= log933 - log2732
= 3log93 - 2log273
= 3(1/log39) - 2(1/log327)
= 3(1/2log33) - 2(1/3log3 3)
= (3/2) - (2/3)
= (9 - 4)/6
= 5/6
Question 3 :
Solve for x :
log8x + log4x + log2x = 11
Solution :
(1/logx8) + (1/logx4) + (1/logx2) = 11
(1/3logx2) + (1/2logx2) + (1/logx2) = 11
(1/logx2)[(1/3) + (1/2) + 1] = 11
(1/logx2) (2 + 3 + 6)/6 = 11
(1/logx2)(11/6) = 11
(1/logx2) = 6
logx2 = 1/6
2 = x1/6
26 = x
x = 64
Question 4 :
Solve for x :
log428x = 2log28
Solution :
(8x)log42 = 23log22
(8x)log42 = 8
log42 = 8/8x
log42 = 1/x
2 = 41/x
2x = 4
2x = 22
x = 2
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