In case of a grouped frequency distribution, the exact values of the variables are not known and as such it is very difficult to locate mode accurately. In such cases, if the class intervals are of equal width, an appropriate value of the mode may be determined by
The class interval with maximum frequency is called the modal class.
Where
l - lower limit of the modal class
f - frequency of the modal class
f1 - frequency of the class just preceding the modal class
f2 - frequency of the class succeeding the modal class
c - width of the class interval
Example :
Find the mode for the following data.
Solution :
To convert discontinuous class interval into continuous class interval, 0.5 has to be substracted from the lower limit and 0.5 has to be added at the upper limit for each class interval.
Modal class is 16 -20 since it has the maximum frequency.
l = 15.5, f = 32, f1 = 16, f2 = 24,
c = 20.5 – 15.5 = 5
f - f1 = 32 - 16 = 16
2f - f1 - f2 = 2(32) - 16 - 24 = 24
Then,
Mode = 15.5 + (16/24) x 5
= 15.5 + 3.33
= 18.83
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
Dec 23, 24 03:47 AM
Dec 23, 24 03:40 AM
Dec 21, 24 02:19 AM