Problem 1 :
Fill in the blanks
(i) The multiplicative inverse of 2 3/5 is _______
Solution :
For any non-zero rational number b there exists a unique rational number 1/b such that b x (1/b) = 1 = (1/b) × b (Multiplicative Inverse property).
First let us convert the mixed fraction into improper fraction.
2 3/5 = (10 + 3)/5 = 13/5
The multiplicative inverse of 13/5 is 5/13.
(ii) If −3 ⋅ (6/-11) = (6/-11) ⋅ x, then x is ________.
Solution :
In order to get same answer for both left hand side and right hand side, we have to remember the commutative law.
a x b = b x a
So, the value of x is -3.
(iii) If distributive property is true for
then x, y, z are ________ , ________ and ________.
Solution :
R.H.S :
= (3/5) (y + z)
= (3/5) ⋅ y + (3/5) ⋅ z ------(1)
L.H.S :
(3/5) ⋅ (-4/9) + (x ⋅ (15/17)) ------(2)
(1) = (2)
(3/5) ⋅ (-4/9) + (x ⋅ (15/17)) = (3/5) ⋅ y + (3/5) ⋅ z
x = 3/5, y = -4/9 and z = 15/17
(iv) If x ⋅ (-55/63) = (-55/63) ⋅ x = 1, then x is called the _________________ of 55/63 .
Solution :
Since the product of x and -55/63 is 1, we say that x is the multiplicative inverse of -55/63.
Hence the value of x is -63/55.
(v) The multiplicative inverse of -1 is ________.
Solution :
The multiplicative inverse of -1 is -1.
Problem 2 :
Say True or False:
(i) (−7/8) × (−23/27) = (−23/27) × (−7/8) illustrates the closure property of rational numbers.
Solution :
The given statement exactly matches with the general form
a x b = b x a
It means commutative property not closure.
Hence the answer is False.
(ii) Associative property is not true for subtraction of rational numbers.
Solution :
(a - b) - c = a - (b - c)
If associative property is true, then it satisfies the above statement.
Let a = 1/2, b = 1/3 and c = 5/6
(a - b) - c = [(1/2) - (1/3)] - 5/6
= (1/6) - (5/6)
= (1-5)/6
= -4/6
= -2/3 -----(1)
a - (b - c) = (1/2) - [(1/3)- 5/6]
= (1/2) - (-3/6)
= (3 + 3)/6
= 1 -----(2)
Hence the answer is True.
(iii) The additive inverse of −11/(-17) is 11/17.
Solution :
The answer is false.
By simplifying 11/17 and 11/17, we will not get 0.
(iv) The product of two negative rational numbers is a positive rational number
Solution :
The answer is True. Because negative times negative is positive.
(v) The multiplicative inverse exists for all rational numbers.
Solution :
For the rational number 0 there is no multiplicative inverse. Hence the answer is false.
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
Dec 30, 24 07:48 PM
Dec 30, 24 07:47 PM
Dec 30, 24 12:57 AM