If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.
Given :
P is the perpendicular bisector L of segment AB and M is the intersection of AB and line L.
To Prove :
PA ≅ PB
Proof :
Statement AB ≅ MB ∠AMP ≅ ∠BMP PM ≅ PM ΔAMP ≅ ΔBMP PB ≅ PB |
Reason Definition of perpendicular bisectors Both angles measure 90° Reflexive property SAS congruence postulate Corresponding parts of congruent triangles are congruent. |
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
Apr 02, 25 12:40 AM
Apr 02, 25 12:35 AM
Apr 02, 25 12:32 AM