Problem 1 :
If the curved surface area of solid sphere is 98.56 cm2, then find the radius of the sphere.
Solution :
Curved surface area of sphere = 98.56 cm2
4 Π r2 = 98.56
4 ⋅ (22/7) ⋅ r² = 98.56
r2 = 98.56 ⋅ (1/4) ⋅ (7/22)
r2 = 98.56 ⋅ (1/4) ⋅ (7/22)
r2 = 7.84
r = √(2.8 ⋅ 2.8)
r = 2.8 cm
So, radius of the sphere is 2.8 cm.
Problem 2 :
If the curved surface area of the solid hemisphere is 2772 sq.cm, then find its total surface area.
Solution :
Curved surface area of hemisphere = 2772 cm2
2Πr2 = 2772
2 ⋅ (22/7) ⋅ r2 = 2772
r2 = 2772 ⋅ (1/2) ⋅ (7/22)
r2 = 441
r = 21
Total surface area of hemisphere = 3Πr2
= 3 ⋅ (22/7) ⋅(21)2
= 4158 cm2
Total surface area of sphere = 4158 cm²
Problem 3 :
Radii of two solid hemispheres are in the ratio 3:5. Find the ratio of their curved surface areas and the ratio of their total surface areas.
Solution :
Let r₁ and r₂ are the radii of two hemispheres
r1 : r2 = 3:5
r1 / r2 = 3/5
r1 = 3r2/5
Curved surface area of hemisphere = 2Πr2
Ratio of curved surface area of two hemisphere
2 Π r2 : 2 Π r2
(3 r2/5)2 : r22
9 : 25
Total surface area of hemisphere = 3Πr²
Ratio of curved surface area of two hemisphere
3Π r12 : 3 Πr22
(3 r₂/5)² : r₂²
9 : 25
Ratio of curved surface area is 9 : 25
Ratio of total surface area is 9 : 25
Problem 4 :
A hemispherical bowl has a radius of 15 cm. If it is filled completely with water and covered with a lid,
(a) find the volume of the water
(b) find the surface area of the bowl (including the lid). Give your answers to 3 significant figures.
Take π = 3.142
Solution :
Radius = 15 cm
a) Volume of hemisphere = (2/3) Πr3
= (2/3) x 3.14 x 153
= 7065 cm3
So, the required volume is 7065 cm3.
b) Surface area bowl = 4Πr2
= 4 x 3.14 x 152
= 39.44 cm2
So, the required surface area is 39.44 cm2
Problem 5 :
A Puffer fish is able to “puff up” when threatened by gulping water and inflating its body. The puffer fish is approximately a sphere with a diameter of 5 inches. Its surface area when inflated is about 1.5 times its normal surface area.
What is the surface area of the fish when it is not puffed up?
Solution :
Surface area of sphere = 4Πr2
Diameter = 5 inches, radius = 5/2 ==> 2.5 inches
Surface area of puffer fish after puff up :
= 4 x 3.14 x (2.5)2
= 78.5 cm2
(Surface area of puffer fish before puff up) x 1.5 = 78.5
Surface area of puffer fish before puff up = 78.5/1.5
= 52.3 cm2
Problem 6 :
A sphere has radius 4.5 cm. Find the volume and surface area of the sphere. Give your answers to 3 significant figures.
Take π = 3.142
Solution :
Radius of sphere = 4.5 cm
Volume of sphere = (4/3) Πr3
= (4/3) x 3.14 x (4.5)3
= (4/3) x 3.14 x 91.12
= 381.48 cm3
So, the required volume of the sphere is 381.48 cm3
Surface area of sphere = 4Πr2
= 4 x 3.14 x (4.5)2
= 254.34 cm2
So, the surface area of the sphere is 254.34 cm2
Problem 7 :
Basketballs used in professional games must have a circumference of 29 1/2 inches. What is the surface area of a basketball used in a professional game?
Solution :
Circumference of the circle = 2Πr
2Πr = 29 1/2 inches
2 x 3.14 x r = 29.5
r = 29.5 / (2 x 3.14)
r = 4.69
Surface area of basket ball = 4Πr2
= 4 x 3.14 x (4.69)2
= 276.27 cm2
So, the surface area of the basket ball is 276.27 cm2
Problem 8 :
A bowl has the form of a hollow hemisphere of radius 8.4 cm. Find the external surface area and the volume of the bowl. Give your answers to 0 significant figures. Take π = 3.142
Solution :
Radius = 8.4 cm
External surface area = 4Πr2
= 4 x 3.14 x 8.42
= 886.23 cm2
So, the external surface area of the sphere = 886.23 cm2
Volume of hemispherical bowl = (2/3)Πr3
= (2/3) x 3.14 x 8.42
= 147.70 cm3
So, volume of the sphere = 147.70 cm3
Problem 9 :
Find the radius of an opened hemisphere whose surface area is 1762 cm² Give your answers to 3 significant figures. Take π = 3.142
Solution :
Surface area of the hemisphere = 1762 cm²
4Πr2 = 1762 cm²
4 x 3.14 r2 = 1762
r2 = 1762 / (4 x 3.14)
r = 13.67
So, the radius of the sphere = 13.67 cm
Problem 10 :
A sphere has radius 12.6 cm. Find the volume and surface area. Give your answers to 3 significant figures. Take π = 3.142
Solution :
Volume of the sphere = (2/3)Πr3
r = 12.6
= (2/3)Π(12.6)3
= 4187.45 cm3
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