PROPORTION 

An equality of two ratios is called a proportion.

Four quantities a, b, c, d are said to be in proportion, if

a : b = c : d (also written as a : b :: c : d)

That is,

a/b = c/d

The quantities a, b, c, d are called terms of the proportion; a, b, c and d are called its first, second, third and fourth terms respectively.

First and fourth terms are called extremes (or extreme terms) and second and third terms are called means (or middle terms).

In a proportion,

product of extremes = product of means

If a : b = c : d are in proportion, then,

ad = bc

This is called cross product rule.

Three quantities a, b, c of the same kind (in same units) are said to be in continuous proportion.

If three quantities a, b, c are in continuous proportion, then the middle term b is called the mean proportional between a and c, a is the first proportional and c is the third proportional.

Since three quantities a, b, c are in continuous proportion, we can write them as

a : b = b : c

Using cross product rule, we can solve for the mean proportion b.

product of means = product of extremes

b2 = ac

Taking square root on both sides,

b = √ac

Solving Problems Using Proportion

Problem 1 :

If x, 2, 10 and 5 are in proportion, find the value of x.

Solution :

x : 2 = 10 : 5

Using cross product rule,

⋅ 5 = 2 ⋅ 10

5x = 20

Divide both sides by 5.

x = 4

Problem 2 :

Find the fourth proportional to 4, 5, 12.

Solution :

Let x be the fourth proportional.

4 : 5 = 12 : x

Using cross product rule,

⋅ x = 5 ⋅ 12

4x = 60

Divide both sides by 4.

x = 15

So, the fourth proportion is 15.

Problem 3 :

Find the third proportion to 2.4, 9.6.

Solution :

Let x be the third proportional.

2.4 : 9.6 = 9.6 : x

Using cross product rule,

2.4 ⋅ x = 9.6 ⋅ 9.6

2.4x = 92.16

Divide both sides by 2.4.

x = 38.4

So, the third proportion is 38.4.

Problem 4 :

Find the mean proportion between 1.25 and 1.8.

Solution :

Let x be the mean proportion between 1.25 and 1.8.

1.25 : x = x : 1.8

x2 = 1.25 ⋅ 1.8

x2 = 2.25

Taking square root on both sides,

x = 1.5

Problem 5 :

If the cost of 7 units of a product is $63, find the cost of 9 units of the same product.

Solution :

Let x be the cost of 9 units.

cost of 7 units ----> $63

cost of 9 units ----> $x

We can form a proportion with the four quantities 7, 9, 63 and x.

7 : 9 = = 63 : x

Using cross product rule,

⋅ x = 9 ⋅ 63

7x = 567

Divide both sides by 7.

x = 81

So, the cost of 9 units is $81.

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