To see from questions 1 to 3, please visit the page "Solving Word Problems Involving Quadratic Equations"
Question 4 :
A girl is twice as old as her sister. Five years hence, the product of their ages (in years) will be 375. Find their present ages.
Solution :
Let "x" be the age of sister
"2x" be the age of girl
Five years hence,
age of sister = x + 5
Age of girl = 2x + 5
Product of their ages = 375
(x + 5)(2x + 5 ) = 375
2x2 + 5x + 10x + 25 - 375 = 0
2x2 + 15x - 350 = 0
2x2 - 20x + 35x - 350 = 0
2x(x - 10) + 35(x -10) = 0
(2x + 35)(x - 10) = 0
x = 10
Hence the age of sister is 10 years, age of girl = 2(10) = 20 years.
Question 5 :
A pole has to be erected at a point on the boundary of a circular ground of diameter 20 m in such a way that the difference of its distances from two diametrically opposite fixed gates P and Q on the boundary is 4 m. Is it possible to do so? If answer is yes at what distance from the two gates should the pole be erected?
Solution :
x2 + (x + 4)2 = 202
x2 + x2 + 2x(4) + 42 = 400
2x2 + 8x + 16 - 400 = 0
2x2 + 8x - 384 = 0
x2 + 4x - 192 = 0
(x + 16)(x- 12) = 0
x + 16 = 0 and x - 12 = 0
x = -16 and x = 12.
Hence required distance is 12 m and 16 m.
Question 6 :
From a group of 2x2 black bees , square root of half of the group went to a tree. Again eight-ninth of the bees went to the same tree. The remaining two got caught up in a fragrant lotus. How many bees were there in total?
Solution :
Total number of bees = 2x2
Number of bees went to tree = (1/2)√x2 = x
Number of bees went to the same tree = (8/9)2x2 = 16x2/9
Remaining number of bees = 2
x + (16x2/9) + 2 = 2x2
9x + 16x2 + 18 = 18x2
18x2- 16x2 - 9x - 18 = 0
2x2 - 9x - 18 = 0
2x2 - 12x + 3x - 18 = 0
2x(x - 6) + 3(x - 6) = 0
(2x + 3)(x - 6) = 0
x - 6 = 0, 2x + 3 = 0
x = 6, x = -3/2 (not possible)
Total number of bees = 2(6)2 = 2(36) = 72
Hence total number of bees = 72.
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