When the denominator of an expression contains a term with a square root or a number under radical sign, the process of converting into an equivalent expression whose denominator is a rational number is called rationalizing the denominator.
If the product of two irrational numbers is rational, then each one is called the rationalizing factor of the other.
Case 1 :
If the denominator is in the form of √a (where a is a rational number).
Then we have to multiply both the numerator and denominator by the same (√a).
Example 1 :
Rationalize the denominator 18/√6
Solution :
Step 1 :
We have to rationalize the denominator. Here we have √6 (in the form of √a). Then we have to multiply the numerator and denominator by √6
Step 2 :
By multiplying the numerators and denominators of first and second fraction , we get
Step 3 :
By simplifications, we get 3√6
Case 2 :
If the denominator is in the form of a ± √b or a ± c √b (where b is a rational number).
Then we have to multiply both the numerator and denominator by its conjugate.
a + √b and a - √b are conjugate of each other.
a + c√b and a - c√b are conjugate of each other.
Example 2 :
Rationalize the denominator
4/(1+2√3)
Solution :
Step 1 :
Here we have (1 + 2√3) (in the form of a + c√b) in the denominator. Then we have to multiply the numerator and denominator by the conjugate of (1 + 2√3).
Conjugate of (1 + 2√3) is (1 - 2√3)
= [4/(1 + 2√3)] ⋅ [(1 - 2√3) / (1 - 2√3)]
= [4(1 - 2√3)/(1 - 2√3)(1 - 2√3)]
= [4(1 - 2√3)/(1 - 2√3)(1 - 2√3)]
(a + b)(a - b) = a2 - b2
(1 - 2√3)(1 - 2√3) = 12 - (2√3)2
= [4(1 - 2√3)/(12 - (2√3)2)
= [4(1 - 2√3)/(1 - (4(3))
= [4(1 - 2√3)/(-11)
= (-4/11) + (2√3/11)
Example 3 :
Rationalize the denominator
(6 + √5)/(6-√5)
Solution :
Step 1 :
Here we have (6-√5) in the denominator. Then we have to multiply the numerator and denominator by the conjugate of (6-√5).
Conjugate of (6-√5) is (6+√5)
= [(6 + √5)/(6-√5)] [(6 + √5)/(6 + √5)]
= (6 + √5)2 / (6-√5)(6 + √5)
(6 + √5)2 = 62 + 2(6)(√5) + (√5)2
= 36 + 12√5 + 5
= 41 + 12√5
Example 4 :
Rationalize the denominator
(2 + √3)/(2 - √3) = x + y√3
and find the value of x and y.
Solution :
(2 + √3)/(2 - √3)
Conjugate of the denominator 2 - √3 is 2 + √3.
= [ (2 + √3) / (2 - √3) ] [ (2 + √3) / (2 + √3) ]
= [ (2 + √3)2/ (2 - √3)(2 + √3) ]
(2 + √3)2
Expanding this using algebraic identity,
(a + b)2 = a2 + 2ab + b2
(2 + √3)2 = 22 + 2(2)√3 + √32
= 4 + 4√3 + 3
= 7 + 4√3